跪求！！我想用C#实现qq抖动窗口。给详细讲解一下代码。谢谢！

Question

不就是让窗体的location晃动一下吗

Answer 1

是否是用timer启发窗体坐标短时间变化?我也是新手以上只是我个人想法

Answer 2

private void button2_Click(object sender, EventArgs e)
        {
            int recordx = this.Left;
            int recordy = this.Top;
            Random random = new Random();
            for (int i = 0; i < 50; i++)
            {
                int x = random.Next(rand);
                int y = random.Next(rand);
                if (x % 2 == 0)
                {
                    this.Left = this.Left + x;
                }
                else
                {
                    this.Left = this.Left - x;
                }
                if (y % 2 == 0)
                {
                    this.Top = this.Top + y;
                }
                else
                {
                    this.Top = this.Top - y;
                }
                System.Threading.Thread.Sleep(1);
            }
            this.Left = recordx;
            this.Top = recordy;
        }

Answer 3

private void button2_Click(object sender, EventArgs e)
        {
            int recordx = this.Left;
            int recordy = this.Top;
            Random random = new Random();
            for (int i = 0; i < 50; i++)
            {
                int x = random.Next(rand);
                int y = random.Next(rand);
                if (x % 2 == 0)
                {
                    this.Left = this.Left + x;
                }
                else
                {
                    this.Left = this.Left - x;
                }
                if (y % 2 == 0)
                {
                    this.Top = this.Top + y;
                }
                else
                {
                    this.Top = this.Top - y;
                }
                System.Threading.Thread.Sleep(1);
            }
            this.Left = recordx;
            this.Top = recordy;
        }
看看MyQQ。

Answer 4

double dob = 0;
        private void timer1_Tick(object sender, EventArgs e)
        {
            //每次增加角度数
            dob += 30;
            //数字3为窗口抖动的半径
            this.Location = new Point(this.Location.X +Convert.ToInt32( Math.Sin(dob)*3), this.Location.Y +Convert.ToInt32( Math.Cos(dob)*3));
            if(dob>720)
            {
                dob = 0;
                timer1.Enabled = false;   
            }
        }

Answer 5

double dob = 0;
        private void timer1_Tick(object sender, EventArgs e)
        {
            //每次增加角度数
            dob += 30;
            //数字3为窗口抖动的半径
            this.Location = new Point(this.Location.X +Convert.ToInt32( Math.Sin(dob)*3), this.Location.Y +Convert.ToInt32( Math.Cos(dob)*3));
            if(dob>720)
            {
                dob = 0;
                timer1.Enabled = false;   
            }
        }