如何读取图像到byte[]

Question

      FileStream strem = new FileStream("imagefile", FileMode.Open);
            byte[] data = new byte[strem.Length];
            strem.Read(data, 0, data.Length);
            strem.Close();
            

Answer 1

using System;
using System.IO;
namespace ConsoleApplication1
{
class Class1
{
[STAThread]
static void Main(string[] args)
{
FileStream fsPic = new FileStream(@"../**.gif",FileMode.Open);
byte[] byPic = new byte[fs.Length];
fsPic.Read(byPic,0,(int)fs.Length);
foreach(byte a in byPic)
Console.Write(a);
}
}
}

Answer 2

string file_name = FileUpload1.FileName;//获取文件名
        string size = FileUpload1.PostedFile.ContentLength.ToString();//获取文件大小
        string type = FileUpload1.PostedFile.ContentType;//获取文件类型
        string houzhui_type = file_name.Substring(file_name.LastIndexOf(".") + 1);//文件后缀名
        string file_path = FileUpload1.PostedFile.FileName; //选中的文件路径和文件名
        
        if (type == "image/pjpeg" || type == "image/gif" || type == "image/png" || type == "image/bmp" || type == "image/x-png" || type == "image/jpeg")
        {
            try
            {
                //保存图片格式数据
                SqlConnection strcon = new SqlConnection(System.Configuration.ConfigurationManager.AppSettings["strcon"]);
                strcon.Open();
                SqlCommand EmailReceive = new SqlCommand("ReceiveEmail", strcon);
                EmailReceive.CommandType = CommandType.StoredProcedure;
                System.Drawing.Image img = System.Drawing.Image.FromFile(file_path);
                //以Jpeg格式存到内存中
                System.IO.MemoryStream ms = new System.IO.MemoryStream();
                img.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg);
                EmailReceive.Parameters.Add("@photo", System.Data.SqlDbType.Image);
                //接收图片二进制数据
                EmailReceive.Parameters["@photo"].Value = ms.ToArray();
                //接收其他数据
                EmailReceive.Parameters.AddWithValue("@from", txtFrom.Text);
                EmailReceive.Parameters.AddWithValue("@to", txtTo.Text);
                EmailReceive.Parameters.AddWithValue("@Comment", txtComments.Text);
                EmailReceive.Parameters.AddWithValue("@status", Email_status);
                EmailReceive.Parameters.AddWithValue("@Text",System.DBNull.Value);
                //销毁
                img.Dispose();
                ms.Dispose();
                ms.Flush();
                Convert.ToInt32(EmailReceive.ExecuteNonQuery());
                //EmailReceive.ExecuteNonQuery();
                strcon.Close();
            }
            catch (Exception exc)
            {                Response.Write("Send failure: " + exc.ToString());
            }
          }

Answer 3

这样：Image img = Image.FromFile(FileName);MemoryStream stream = new MemoryStream();
img.Save(stream,ImageFormat.Jpeg);
byte[] bts = stream.GetBuffer();

Answer 4

                    MemoryStream stream = new MemoryStream();
                    stream.Write(mydata, 0, mydata.Length);
                    Image myImage = Image.FromStream(stream);
mydata是byte[]类型的 存的是图片的二进制值

Answer 5

FileStream strem = new FileStream("imagefile", FileMode.Open);
  byte[] data = new byte[strem.Length];
  strem.Read(data, 0, data.Length);
  strem.Close();