请教!鼠标移动画图时怎么才能不让屏幕闪烁?

Question

不知道 这个能帮你不  private bool m_MouseLine = false;
        private Point _Point = Point.Empty;
        private void panel2_MouseDown(object sender, MouseEventArgs e)
        {
            _Point.X = e.X;
            _Point.Y = e.Y;
            m_MouseLine = true;
        }        private void panel2_MouseMove(object sender, MouseEventArgs e)
        {
            panel2.Refresh();
            if (m_MouseLine)
            {
                Graphics _Graphics = Graphics.FromHwnd(panel2.Handle);
                _Graphics.DrawLine(new Pen(Brushes.Black, 1), _Point, new Point(e.X, e.Y));
                
                _Graphics.Dispose();
            }            
        }        private void panel2_MouseUp(object sender, MouseEventArgs e)
        {
            //处理图形            panel2.Refresh();
        }

Answer 1

试验了,还是闪,如果要是panel控件能透明就好了,也许可以解决.

Answer 2

blog.csdn.net/dunao
看看这个吧不闪

Answer 3

以前回答过，再贴一遍双缓冲（和DirectDraw一个原理） 
namespace WindowsFormsApplication10
{
    public partial class Form1 : Form
    {
        Bitmap OrgBmp = null;
        Bitmap CacheBmp = null;
        public Form1()
        {
            InitializeComponent();            pictureBox1.Image = new Bitmap(400, 400);
            pictureBox1.Size = new Size(400, 400);
            Graphics g = Graphics.FromImage(pictureBox1.Image);
            g.FillEllipse(new SolidBrush(Color.Red), new Rectangle(0, 0, 400, 400));
            g.Dispose();
            OrgBmp = new Bitmap(pictureBox1.Image);
        }        private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
        {
            CacheBmp = new Bitmap(OrgBmp);
            Graphics g = Graphics.FromImage(CacheBmp);
            g.FillRectangle(new SolidBrush(Color.Black), new Rectangle(e.Location, new Size(30, 30)));
            g.Dispose();
            pictureBox1.Image = CacheBmp; 
        }
    }
}