在orm中怎么给类的属性赋值？

Question

using System;
using System.Collections.Generic;
using System.Data;
using System.Linq;
using System.Reflection;
namespace ConsoleApplication6
{
    [AttributeUsage(AttributeTargets.Class,Inherited=false,AllowMultiple=false)]
    public sealed class NovDBAttribute : Attribute
    { 
        private string _tableName;
        public NovDBAttribute()
        {}
        public NovDBAttribute(string tableName)
        {
            _tableName=tableName;
        }
    }
    [AttributeUsage(AttributeTargets.Property,Inherited=false,AllowMultiple=false)]
    public sealed class NovProAttribute : Attribute
    {
        public Type _type;
        public bool _enableNull;
        public string _proName;
        public NovProAttribute(){}
        public NovProAttribute(Type type,bool enableNull,string proName)
        {
            _type=type;
            _enableNull=enableNull;
            _proName=proName;
        }
    }
    [NovDB("userTable")]
    public class People
    {
        [NovPro(typeof(Int32),false,"id")]
        public int ID{set;get;}
        [NovPro(typeof(String), true, "name")]
        public string name{set;get;}
        [NovPro(typeof(String), true, "sex")]
        public string sex{set;get;}
    }
    class Program
    {
        static void Main(string[] args)
        {
            DataTable table = new DataTable("userTable");
            DataColumn idcolumn = new DataColumn("id", typeof(Int32));
            DataColumn namecolumn = new DataColumn("name", typeof(String));
            DataColumn sexcolumn=new DataColumn("sex",typeof(String));
            table.Columns.Add(idcolumn);
            table.Columns.Add(namecolumn);
            table.Columns.Add(sexcolumn);
            table.Rows.Add(1,"jak","man");
            table.Rows.Add(1, "join", "man");
            table.Rows.Add(1, "ross", "woman");            List<People> p = RomToT<People>(table);
        }
        /// <summary>
        /// Table转化为类实例列表
        /// </summary>
        /// <typeparam name="T"></typeparam>
        /// <param name="table">表</param>
        /// <returns></returns>
        private static List<T> RomToT<T>(DataTable table) where T : class, new()
        {
            List<T> objList =new List<T>();
            Type t = typeof(T);
            object[] att = t.GetCustomAttributes(false);
            PropertyInfo[] pro=t.GetProperties();
            NovProAttribute[] proattributeArray = new NovProAttribute[pro.Length]; //T类属性的特性属性
            for (var i = 0; i < pro.Length; ++i)
            {
                object[] proAtt =pro[i].GetCustomAttributes(false);
                proattributeArray[i] = proAtt == null || proAtt.Count() == 0 ? null : proAtt[0] as NovProAttribute; 
            }
            for (var i = 0; i < table.Rows.Count; ++i)
            {
                T obj = new T();
                //????????????这里怎么把tableRow的值赋给T的属性？即怎么生成类型T的实例？
            }
            object retValue = "";
            return retValue as List<T>;
        }
    }
}
如上面的例子问号处，在RomToT方法中怎么把tableRow的值赋给T类的obj的属性实例对象类ORM

Answer 1

反射赋值
 T obj = new T();
                Type type = obj.GetType();
                foreach (PropertyInfo pi in type.GetProperties())
                {
                    if (table.Columns.Contains(pi.Name))
                        pi.SetValue(obj, table.Rows[i][pi.Name]);
                }
                //????????????这里怎么把tableRow的值赋给T的属性？即怎么生成类型T的实例？