多线程问题

Question

请高手指点在线等。按钮代码如下：        List<ManualResetEvent> doneEvents;
        ManualResetEvent doneEvent;
        private void btnMutlieAdd_Click(object sender, EventArgs e)
        {
            DialogResult dr = openFileDialog1.ShowDialog();
            if (dr == DialogResult.OK)
            {
                ///此处省略代码
                for()///此处省略代码
                {
                    doneEvent = new ManualResetEvent(false);
                    doneEvents.Add( doneEvent);
                    ThreadPool.QueueUserWorkItem(ThreadPoolCallback1, qqInfo);
                }                //等待所有结束
                WaitHandle.WaitAll(doneEvents.ToArray());
            }
        }        ////[STAThread]
        [MTAThread]
        static void Main()
        {
            Application.EnableVisualStyles();
            Application.SetCompatibleTextRenderingDefault(false);
            Application.Run(new frmMain());
        }
如果用MTAThread的话， DialogResult dr = openFileDialog1.ShowDialog(); 这里就
   异常：
    在可以调用 OLE 之前，必须将当前线程设置为单线程单元(STA)模式。请确保您的 Main 函数带有 STAThreadAttribute 标记。 只有将调试器附加到该进程才会引发此异常。改成[STAThread]的话，WaitHandle.WaitAll(doneEvents.ToArray());就
异常：
     不支持一个 STA 线程上针对多个句柄的 WaitAll。是不是openFileDialog和WaitAll不能同时用？

Answer 1

WaitHandle.WaitAll(doneEvents.ToArray());
=>
doneEvents.ForEach(x => x.WaitOne());

Answer 2

private void btnMutlieAdd_Click(object sender, EventArgs e)
{
       DialogResult dr = openFileDialog1.ShowDialog(); 
       if (dr == DialogResult.OK)
       {
           ThreadPool.QueueUserWorkItem(DoWork, qqInfo);
       }
 }       void DoWork(object state)
       {
        ///此处省略代码
                for()///此处省略代码
                {
                    doneEvent = new ManualResetEvent(false);
                    doneEvents.Add(doneEvent);
                    ThreadPool.QueueUserWorkItem(ThreadPoolCallback1, state);
                }                //等待所有结束
                WaitHandle.WaitAll(doneEvents.ToArray());
         }