在下面这个串口程序中怎么实现收到的数据是十进制的

Question

 我想把收到的数据形式是“A23”或者"B34"，并根据A或B分别显示数据，“23”或“34”才是数据位，怎样实现数据是十进制显示并且没只显示数据位。
private void SpCom_DataReceived(object sender, SerialDataReceivedEventArgs e)
        {
            try
            {
                if (IsReceive || IsClose) return;                System.Threading.Thread.Sleep(100);//接收数据时延时时间，可根据数据大小调整值
                int len = SpCom.BytesToRead;
                if (len < 1) return;//此处可根据数据的大小设置                 IsReceive = true;                byte[] data = new byte[len];            
                SpCom.Read(data, 0, len);//从串口读取信息 
              
                string temp3 = ConvertByteToHexstr(data);
                string temp4 = delspace(temp3);
                n = temp4.Length;                                         
                textBox1.Invoke(new EventHandler(delegate
                {
                    if (temp4[0] == 'A')
                    {           
                       textBox1.Text = temp4;
                        m = textBox2.Text.Length;                    }
                       
                }));
                textBox2.Invoke(new EventHandler(delegate
                {
                   
                    if (temp4[0]== 'B')
                    {
                        textBox2.Text = temp4;
                        m = textBox2.Text.Length;                       
                    }     
                }));
                           }
            catch
            {            }
            finally
            {
                IsReceive = false;
            }        }

Answer 1

自己去掉A，如果A后面是十六进制字符串，那就转为intint.Parse("FF", System.Globalization.NumberStyles.HexNumber)