环境:vs.2003 C#
需求:
/*使用二个64位的验证密钥,KeyA和KeyB。
a) 计算算法的数据源包括:
账号、失效期和代码,从左至右顺序编排。
例如19位账号、4位失效期和3位代码组成26个字符的数据源。
b) 将上述数据源扩展成128位二进制数据(不足128位右补二进制0)。
c) 将128位二进制数据分成两个64位的数据块。最左边的64位为Block1,最右边的64位为Block2。
d) 使用KeyA对Block1进行加密。
e) 将Block1的加密结果与Block2进行异或。使用KeyA对异或结果进行加密。
f) 使用KeyB对加密结果进行解密。
g) 使用KeyA对解密结果进行加密。
h) 从左至右将加密结果中的数字(0-9)抽出,组成一组数字。
i) 从左至右将加密结果中的字符(A-F)抽出,减10后将余数组成一组数字,排列在步骤(8)的数字之后。
j) 步骤(9)的左边第一组三位数即为结果值。*/例:
账 号:4123 4567 8901 2345(例子省去几位) KeyA:0123 4567 89AB CDEF
失效期:8701 KeyB:FEDC BA98 7654 3210
代码:111第一步:数据源为4123456789012345 8701 111
第二步:扩展为4123 4567 8901 2345 8701 1110 0000 0000
第三步:Block1=4123 4567 8901 2345
Block2=8701 1110 0000 0000
第四步:用KeyA对Block1加密;
结果为:B76A DDCE 71CC C6BE
第五步:将结果与Block2异或,结果为:306B CCDE 71CC C6BE
再用KeyA加密, 结果为:BAE6 746F 6DE1 F0E6
第六步:用KeyB解密, 结果为:B262 ABCB 9DE9 9A63
第七步:用KeyA加密, 结果为:8D56 25FA 7801 1A0C
第八步:抽出结果中的数字, 结果为:8562 5780 110
第九步:抽出结果中的字符, 结果为:DFAA C
减10后, 结果为:3500 2
连接到第八步的结果之后为: 8562 5780 1103 5002
第十步 最左边三位数就是算法需要得到的值856。
求算法思路及代码。
需求:
/*使用二个64位的验证密钥,KeyA和KeyB。
a) 计算算法的数据源包括:
账号、失效期和代码,从左至右顺序编排。
例如19位账号、4位失效期和3位代码组成26个字符的数据源。
b) 将上述数据源扩展成128位二进制数据(不足128位右补二进制0)。
c) 将128位二进制数据分成两个64位的数据块。最左边的64位为Block1,最右边的64位为Block2。
d) 使用KeyA对Block1进行加密。
e) 将Block1的加密结果与Block2进行异或。使用KeyA对异或结果进行加密。
f) 使用KeyB对加密结果进行解密。
g) 使用KeyA对解密结果进行加密。
h) 从左至右将加密结果中的数字(0-9)抽出,组成一组数字。
i) 从左至右将加密结果中的字符(A-F)抽出,减10后将余数组成一组数字,排列在步骤(8)的数字之后。
j) 步骤(9)的左边第一组三位数即为结果值。*/例:
账 号:4123 4567 8901 2345(例子省去几位) KeyA:0123 4567 89AB CDEF
失效期:8701 KeyB:FEDC BA98 7654 3210
代码:111第一步:数据源为4123456789012345 8701 111
第二步:扩展为4123 4567 8901 2345 8701 1110 0000 0000
第三步:Block1=4123 4567 8901 2345
Block2=8701 1110 0000 0000
第四步:用KeyA对Block1加密;
结果为:B76A DDCE 71CC C6BE
第五步:将结果与Block2异或,结果为:306B CCDE 71CC C6BE
再用KeyA加密, 结果为:BAE6 746F 6DE1 F0E6
第六步:用KeyB解密, 结果为:B262 ABCB 9DE9 9A63
第七步:用KeyA加密, 结果为:8D56 25FA 7801 1A0C
第八步:抽出结果中的数字, 结果为:8562 5780 110
第九步:抽出结果中的字符, 结果为:DFAA C
减10后, 结果为:3500 2
连接到第八步的结果之后为: 8562 5780 1103 5002
第十步 最左边三位数就是算法需要得到的值856。
求算法思路及代码。
解决方案 »
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我拿"4123456789012345","0123456789ABCDEF"加密怎么也加不出来B76A DDCE 71CC C6BE
然后第二步转换成二进制,向右补齐128位,在第三步一分为二
账号: 6224219601000004994
失效期:4912
代码:120
第一步:62242196010000049944912120
第二步:622421960100000499449121200000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
第三步:
Block1:6224219601000004994491212000000000000000000000000000000000000000
Block2:000000000000000000000000000000000000000000000000000000000000
第四步往后我还不知道怎么具体做
结果为:B76A DDCE 71CC C6BE
怎么来的?
你的需求方是干嘛的。。怎么都是弄加密呢。那你得问一下他怎么加密出来的,DES的运算模式就有5种。。
int Get_CSD(char *kstr,char *mdte,char *mfdm,char *r_cvn)
{
/*************************************************************
*账号(kstr)+有效期(mdte)+代码(mfdm)
**************************************************************/
unsigned char KeyA[8]={0xd3,0x1a,0xe7,0x29,0x5b,0x48,0xcf,0x06};
unsigned char KeyB[8]={0x2b,0x62,0x13,0x7d,0x0b,0xfb,0x9a,0x68}; unsigned char data[8],data1[8],tmstr1[5],result[17]; char mstr[33],bstr[129],tmstr[3];
char block1[17],block2[17];
int tlen,i,len,l;
char t1,t2,t3[2];
char cstr[2],cestr[2],tnum[17],cnum[17],tstr[17],testr[17];
char rnum[17];
char cvn[4]; tlen=32; /**************************************************************
*将账号+有效期+代码扩展到128位数据源(不足128右补二进制0)
**************************************************************/
memset(mstr,'\0',sizeof(mstr)); pub_base_strpack(kstr);
pub_base_strpack(mdte);
pub_base_strpack(mfdm); strcpy(mstr,kstr);
strcat(mstr,mdte);
strcat(mstr,mfdm); for (i=strlen(mstr);i<tlen;i++)
{
strcat(mstr,"0");
} /**************************************************************
*将128位数据源分成两个64位的数据块。最左边64位为block1,最右边
*64位为block2
**************************************************************/
memset(block1,'\0',sizeof(block1));
memset(block2,'\0',sizeof(block2)); strncpy(block1,mstr,16); strncpy(block2,mstr+16,16); /**************************************************************
*block1转换为8字节的十六进制字符串data
**************************************************************/
memset(data,'\0',sizeof(data));
memset(tmstr,'\0',sizeof(tmstr));
memset(tmstr1,'\0',sizeof(tmstr1)); len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,block1+len,2);
sub_asc_to_bcd(tmstr1,tmstr,2,0);
data[i]=tmstr1[0];
len=len+2;
} /**************************************************************
*将data数据用KeyA加密,结果为result
**************************************************************/
memset(result,'\0',sizeof(result)); des(data,result,KeyA,1); /**************************************************************
*将result,转换为8字节的字符串tstr
**************************************************************/
memset(tstr,'\0',sizeof(tstr));
memset(cstr,'\0',sizeof(cstr)); for(i=0;i<8;i++)
{
sprintf(cstr,"%02x", result[i]);
strcat(tstr,cstr);
} /**************************************************************
*将tstr同block2进行异或,结果为testr
**************************************************************/
memset(testr,'\0',sizeof(testr));
memset(cestr,'\0',sizeof(cestr)); for(i=0;i<16;i++)
{
if (tstr[i]>='a' || tstr[i]>='A')
t1=tstr[i]-'a'+10;
else
t1=tstr[i]-'0';
if (block2[i]>='a' || block2[i]>='A')
t2=block2[i]-'a'+10;
else
t2=block2[i]-'0';
sprintf(cestr,"%x", t1^t2);
strcat(testr,cestr);
} /**************************************************************
*testr转换为8字节的十六进制字符串data1
**************************************************************/
memset(data1,'\0',sizeof(data1));
memset(tmstr,'\0',sizeof(tmstr));
memset(tmstr1,'\0',sizeof(tmstr1));
len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,testr+len,2);
sub_asc_to_bcd(tmstr1,tmstr,2,0);
data1[i]=tmstr1[0];
len=len+2;
} /**************************************************************
*将data1数据用KeyA加密,结果为result
**************************************************************/
memset(result,'\0',sizeof(result));
des(data1,result,KeyA,1);
/**************************************************************
*将result数据用KeyB解密,结果为result
**************************************************************/
des(result,result,KeyB,0);
/**************************************************************
*将result数据用KeyA加密,结果为result
**************************************************************/
des(result,result,KeyA,1); /**************************************************************
*将result转换为8字节十六进制数据tstr
**************************************************************/
memset(cstr,'\0',sizeof(cstr));
memset(tstr,'\0',sizeof(tstr)); for(i=0;i<8;i++)
{
sprintf(cstr,"%02x", result[i]);
strcat(tstr,cstr);
} /**************************************************************
*将tstr中的数字提取出来,结果tnum;
*将tstr中的字符抽出,减10后将余数组成一组数字cnum,放在tnum后
**************************************************************/
memset(tnum,'\0',sizeof(tnum));
memset(cnum,'\0',sizeof(cnum)); for(i=0;i<16;i++)
{
if (tstr[i]>='0' && tstr[i]<='9')
{
sprintf(t3,"%c",tstr[i] );
strcat(tnum,t3);
}
if ((tstr[i]>='a' && tstr[i]<='f') ||
(tstr[i]>='A' && tstr[i]<='F'))
{
sprintf(t3,"%d",tstr[i]-'a');
strcat(cnum,t3);
}
} memset(rnum,'\0',sizeof(rnum));
strcpy(rnum,tnum);
strcat(rnum,cnum); memset(cvn,'\0',sizeof(cvn)); strncpy(cvn,rnum,3); strcpy(r_cvn,cvn); return 0;
}
账号、失效期和代码,从左至右顺序编排。
例如19位账号、4位失效期和3位代码组成26个字符的数据源。
b) 将上述数据源扩展成128位二进制数据(不足128位右补二进制0)。
c) 将128位二进制数据分成两个64位的数据块。最左边的64位为Block1,最右边的64位为Block2。 这时Block1的值是不是二进制的?
d) 使用KeyA对Block1进行加密。这里是不是对二进制的Block1进行加密
e) 将Block1的加密结果与Block2进行异或。使用KeyA对异或结果进行加密。
第一步:数据源为4123456789012345 8701 111
第二步:扩展为4123 4567 8901 2345 8701 1110 0000 0000
第三步:Block1=4123 4567 8901 2345 如果上面都是二进制的话这里Block1的值不应该是这个,应该是1110101001100100001100011001001001111101111101111001才对呀,如果不是这个值那上面转成二进制有何用?
Block2=8701 1110 0000 0000
{
unsigned char bufout[64],kwork[56],worka[48],kn[48],buffer[64],key[64];
unsigned char nbrofshift, temp1, temp2;
int valindex;
register i, j, k, iter; /* INITIALIZE THE TABLES */
/* Table - s1 */
static unsigned char s1[4][16] = {
14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,
0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8,
4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0,
15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13 }; /* Table - s2 */
static unsigned char s2[4][16] = {
15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10,
3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5,
0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15,
13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9 }; /* Table - s3 */
static unsigned char s3[4][16] = {
10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8,
13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1,
13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7,
1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12 }; /* Table - s4 */
static unsigned char s4[4][16] = {
7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15,
13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9,
10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4,
3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14 }; /* Table - s5 */
static unsigned char s5[4][16] = {
2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9,
14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6,
4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14,
11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3 }; /* Table - s6 */
static unsigned char s6[4][16] = {
12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11,
10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8,
9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6,
4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13 }; /* Table - s7 */
static unsigned char s7[4][16] = {
4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1,
13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6,
1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2,
6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12 }; /* Table - s8 */
static unsigned char s8[4][16] = {
13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7,
1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2,
7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8,
2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11 }; /* Table - Shift */
static unsigned char shift[16] = {
1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1 }; /* Table - Binary */
static unsigned char binary[64] = {
0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1,
0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 1, 1,
1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 1, 0, 1, 0, 1, 1,
1, 1, 0, 0, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 1, 1 }; /* MAIN PROCESS */
/* Convert from 64-bit key into 64-byte key */
for (i = 0; i < 8; i++) {
key[8*i] = ((j = *(inkey + i)) / 128) % 2;
key[8*i+1] = (j / 64) % 2;
key[8*i+2] = (j / 32) % 2;
key[8*i+3] = (j / 16) % 2;
key[8*i+4] = (j / 8) % 2;
key[8*i+5] = (j / 4) % 2;
key[8*i+6] = (j / 2) % 2;
key[8*i+7] = j % 2;
} /* Convert from 64-bit data into 64-byte data */
for (i = 0; i < 8; i++) {
buffer[8*i] = ((j = *(source + i)) / 128) % 2;
buffer[8*i+1] = (j / 64) % 2;
buffer[8*i+2] = (j / 32) % 2;
buffer[8*i+3] = (j / 16) % 2;
buffer[8*i+4] = (j / 8) % 2;
buffer[8*i+5] = (j / 4) % 2;
buffer[8*i+6] = (j / 2) % 2;
buffer[8*i+7] = j % 2;
} /* Initial Permutation of Data */
bufout[ 0] = buffer[57];
bufout[ 1] = buffer[49];
bufout[ 2] = buffer[41];
bufout[ 3] = buffer[33];
bufout[ 4] = buffer[25];
bufout[ 5] = buffer[17];
bufout[ 6] = buffer[ 9];
bufout[ 7] = buffer[ 1];
bufout[ 8] = buffer[59];
bufout[ 9] = buffer[51];
bufout[10] = buffer[43];
bufout[11] = buffer[35];
bufout[12] = buffer[27];
bufout[13] = buffer[19];
bufout[14] = buffer[11];
bufout[15] = buffer[ 3];
bufout[16] = buffer[61];
bufout[17] = buffer[53];
bufout[18] = buffer[45];
bufout[19] = buffer[37];
bufout[20] = buffer[29];
bufout[21] = buffer[21];
bufout[22] = buffer[13];
bufout[23] = buffer[ 5];
bufout[24] = buffer[63];
bufout[25] = buffer[55];
bufout[26] = buffer[47];
bufout[27] = buffer[39];
bufout[28] = buffer[31];
bufout[29] = buffer[23];
bufout[30] = buffer[15];
bufout[31] = buffer[ 7];
bufout[32] = buffer[56];
bufout[33] = buffer[48];
bufout[34] = buffer[40];
bufout[35] = buffer[32];
bufout[36] = buffer[24];
bufout[37] = buffer[16];
bufout[38] = buffer[ 8];
bufout[39] = buffer[ 0];
bufout[40] = buffer[58];
bufout[41] = buffer[50];
bufout[42] = buffer[42];
bufout[43] = buffer[34];
bufout[44] = buffer[26];
bufout[45] = buffer[18];
bufout[46] = buffer[10];
bufout[47] = buffer[ 2];
bufout[48] = buffer[60];
bufout[49] = buffer[52];
bufout[50] = buffer[44];
bufout[51] = buffer[36];
bufout[52] = buffer[28];
bufout[53] = buffer[20];
bufout[54] = buffer[12];
bufout[55] = buffer[ 4];
bufout[56] = buffer[62];
bufout[57] = buffer[54];
bufout[58] = buffer[46];
bufout[59] = buffer[38];
bufout[60] = buffer[30];
bufout[61] = buffer[22];
bufout[62] = buffer[14];
bufout[63] = buffer[ 6];
/* Initial Permutation of Key */
kwork[ 0] = key[56];
kwork[ 1] = key[48];
kwork[ 2] = key[40];
kwork[ 3] = key[32];
kwork[ 4] = key[24];
kwork[ 5] = key[16];
kwork[ 6] = key[ 8];
kwork[ 7] = key[ 0];
kwork[ 8] = key[57];
kwork[ 9] = key[49];
kwork[10] = key[41];
kwork[11] = key[33];
kwork[12] = key[25];
kwork[13] = key[17];
kwork[14] = key[ 9];
kwork[15] = key[ 1];
kwork[16] = key[58];
kwork[17] = key[50];
kwork[18] = key[42];
kwork[19] = key[34];
kwork[20] = key[26];
kwork[21] = key[18];
kwork[22] = key[10];
kwork[23] = key[ 2];
kwork[24] = key[59];
kwork[25] = key[51];
kwork[26] = key[43];
kwork[27] = key[35];
kwork[28] = key[62];
kwork[29] = key[54];
kwork[30] = key[46];
kwork[31] = key[38];
kwork[32] = key[30];
kwork[33] = key[22];
kwork[34] = key[14];
kwork[35] = key[ 6];
kwork[36] = key[61];
kwork[37] = key[53];
kwork[38] = key[45];
kwork[39] = key[37];
kwork[40] = key[29];
kwork[41] = key[21];
kwork[42] = key[13];
kwork[43] = key[ 5];
kwork[44] = key[60];
kwork[45] = key[52];
kwork[46] = key[44];
kwork[47] = key[36];
kwork[48] = key[28];
kwork[49] = key[20];
kwork[50] = key[12];
kwork[51] = key[ 4];
kwork[52] = key[27];
kwork[53] = key[19];
kwork[54] = key[11];
kwork[55] = key[ 3]; /* 16 Iterations */
for (iter = 1; iter < 17; iter++) {
for (i = 0; i < 32; i++)
buffer[i] = bufout[32+i];
/* Calculation of F(R, K) */
/* Permute - E */
worka[ 0] = buffer[31];
worka[ 1] = buffer[ 0];
worka[ 2] = buffer[ 1];
worka[ 3] = buffer[ 2];
worka[ 4] = buffer[ 3];
worka[ 5] = buffer[ 4];
worka[ 6] = buffer[ 3];
worka[ 7] = buffer[ 4];
worka[ 8] = buffer[ 5];
worka[ 9] = buffer[ 6];
worka[10] = buffer[ 7];
worka[11] = buffer[ 8];
worka[12] = buffer[ 7];
worka[13] = buffer[ 8];
worka[14] = buffer[ 9];
worka[15] = buffer[10];
worka[16] = buffer[11];
worka[17] = buffer[12];
worka[18] = buffer[11];
worka[19] = buffer[12];
worka[20] = buffer[13];
worka[21] = buffer[14];
worka[22] = buffer[15];
worka[23] = buffer[16];
worka[24] = buffer[15];
worka[25] = buffer[16];
worka[26] = buffer[17];
worka[27] = buffer[18];
worka[28] = buffer[19];
worka[29] = buffer[20];
worka[30] = buffer[19];
worka[31] = buffer[20];
worka[32] = buffer[21];
worka[33] = buffer[22];
worka[34] = buffer[23];
worka[35] = buffer[24];
worka[36] = buffer[23];
worka[37] = buffer[24];
worka[38] = buffer[25];
worka[39] = buffer[26];
worka[40] = buffer[27];
worka[41] = buffer[28];
worka[42] = buffer[27];
worka[43] = buffer[28];
worka[44] = buffer[29];
worka[45] = buffer[30];
worka[46] = buffer[31];
worka[47] = buffer[ 0];
if (flg) {
nbrofshift = shift[iter-1];
for (i = 0; i < (int) nbrofshift; i++) {
temp1 = kwork[0];
temp2 = kwork[28];
for (j = 0; j < 27; j++) {
kwork[j] = kwork[j+1];
kwork[j+28] = kwork[j+29];
}
kwork[27] = temp1;
kwork[55] = temp2;
}
} else if (iter > 1) {
nbrofshift = shift[17-iter];
for (i = 0; i < (int) nbrofshift; i++) {
temp1 = kwork[27];
temp2 = kwork[55];
for (j = 27; j > 0; j--) {
kwork[j] = kwork[j-1];
kwork[j+28] = kwork[j+27];
}
kwork[0] = temp1;
kwork[28] = temp2;
}
} /* Permute kwork - PC2 */
kn[ 0] = kwork[13];
kn[ 1] = kwork[16];
kn[ 2] = kwork[10];
kn[ 3] = kwork[23];
kn[ 4] = kwork[ 0];
kn[ 5] = kwork[ 4];
kn[ 6] = kwork[ 2];
kn[ 7] = kwork[27];
kn[ 8] = kwork[14];
kn[ 9] = kwork[ 5];
kn[10] = kwork[20];
kn[11] = kwork[ 9];
kn[12] = kwork[22];
kn[13] = kwork[18];
kn[14] = kwork[11];
kn[15] = kwork[ 3];
kn[16] = kwork[25];
kn[17] = kwork[ 7];
kn[18] = kwork[15];
kn[19] = kwork[ 6];
kn[20] = kwork[26];
kn[21] = kwork[19];
kn[22] = kwork[12];
kn[23] = kwork[ 1];
kn[24] = kwork[40];
kn[25] = kwork[51];
kn[26] = kwork[30];
kn[27] = kwork[36];
kn[28] = kwork[46];
kn[29] = kwork[54];
kn[30] = kwork[29];
kn[31] = kwork[39];
kn[32] = kwork[50];
kn[33] = kwork[44];
kn[34] = kwork[32];
kn[35] = kwork[47];
kn[36] = kwork[43];
kn[37] = kwork[48];
kn[38] = kwork[38];
kn[39] = kwork[55];
kn[40] = kwork[33];
kn[41] = kwork[52];
kn[42] = kwork[45];
kn[43] = kwork[41];
kn[44] = kwork[49];
kn[45] = kwork[35];
kn[46] = kwork[28];
kn[47] = kwork[31];
/* KS Function End */ /* worka XOR kn */
for (i = 0; i < 48; i++)
worka[i] = worka[i] ^ kn[i]; /* 8 s-functions */
valindex = s1[2*worka[ 0]+worka[ 5]]
[2*(2*(2*worka[ 1]+worka[ 2])+
worka[ 3])+worka[ 4]];
valindex = valindex * 4;
kn[ 0] = binary[0+valindex];
kn[ 1] = binary[1+valindex];
kn[ 2] = binary[2+valindex];
kn[ 3] = binary[3+valindex];
valindex = s2[2*worka[ 6]+worka[11]]
[2*(2*(2*worka[ 7]+worka[ 8])+
worka[ 9])+worka[10]];
valindex = valindex * 4;
kn[ 4] = binary[0+valindex];
kn[ 5] = binary[1+valindex];
kn[ 6] = binary[2+valindex];
kn[ 7] = binary[3+valindex];
valindex = s3[2*worka[12]+worka[17]]
[2*(2*(2*worka[13]+worka[14])+
worka[15])+worka[16]];
valindex = valindex * 4;
kn[ 8] = binary[0+valindex];
kn[ 9] = binary[1+valindex];
kn[10] = binary[2+valindex];
kn[11] = binary[3+valindex];
valindex = s4[2*worka[18]+worka[23]]
[2*(2*(2*worka[19]+worka[20])+
worka[21])+worka[22]];
valindex = valindex * 4;
kn[12] = binary[0+valindex];
kn[13] = binary[1+valindex];
kn[14] = binary[2+valindex];
kn[15] = binary[3+valindex];
valindex = s5[2*worka[24]+worka[29]]
[2*(2*(2*worka[25]+worka[26])+
worka[27])+worka[28]];
valindex = valindex * 4;
kn[16] = binary[0+valindex];
kn[17] = binary[1+valindex];
kn[18] = binary[2+valindex];
kn[19] = binary[3+valindex];
valindex = s6[2*worka[30]+worka[35]]
[2*(2*(2*worka[31]+worka[32])+
worka[33])+worka[34]];
valindex = valindex * 4;
kn[20] = binary[0+valindex];
kn[21] = binary[1+valindex];
kn[22] = binary[2+valindex];
kn[23] = binary[3+valindex];
valindex = s7[2*worka[36]+worka[41]]
[2*(2*(2*worka[37]+worka[38])+
worka[39])+worka[40]];
valindex = valindex * 4;
kn[24] = binary[0+valindex];
kn[25] = binary[1+valindex];
kn[26] = binary[2+valindex];
kn[27] = binary[3+valindex];
valindex = s8[2*worka[42]+worka[47]]
[2*(2*(2*worka[43]+worka[44])+
worka[45])+worka[46]];
valindex = valindex * 4;
kn[28] = binary[0+valindex];
kn[29] = binary[1+valindex];
kn[30] = binary[2+valindex];
kn[31] = binary[3+valindex];
/* Permute - P */
worka[ 0] = kn[15];
worka[ 1] = kn[ 6];
worka[ 2] = kn[19];
worka[ 3] = kn[20];
worka[ 4] = kn[28];
worka[ 5] = kn[11];
worka[ 6] = kn[27];
worka[ 7] = kn[16];
worka[ 8] = kn[ 0];
worka[ 9] = kn[14];
worka[10] = kn[22];
worka[11] = kn[25];
worka[12] = kn[ 4];
worka[13] = kn[17];
worka[14] = kn[30];
worka[15] = kn[ 9];
worka[16] = kn[ 1];
worka[17] = kn[ 7];
worka[18] = kn[23];
worka[19] = kn[13];
worka[20] = kn[31];
worka[21] = kn[26];
worka[22] = kn[ 2];
worka[23] = kn[ 8];
worka[24] = kn[18];
worka[25] = kn[12];
worka[26] = kn[29];
worka[27] = kn[ 5];
worka[28] = kn[21];
worka[29] = kn[10];
worka[30] = kn[ 3];
worka[31] = kn[24]; /* bufout XOR worka */
for (i = 0; i < 32; i++) {
bufout[i+32] = bufout[i] ^ worka[i];
bufout[i] = buffer[i];
}
} /* End of Iter */ /* Prepare Output */
for (i = 0; i < 32; i++) {
j = bufout[i];
bufout[i] = bufout[32+i];
bufout[32+i] = j;
}
/* Inverse Initial Permutation */
buffer[ 0] = bufout[39];
buffer[ 1] = bufout[ 7];
buffer[ 2] = bufout[47];
buffer[ 3] = bufout[15];
buffer[ 4] = bufout[55];
buffer[ 5] = bufout[23];
buffer[ 6] = bufout[63];
buffer[ 7] = bufout[31];
buffer[ 8] = bufout[38];
buffer[ 9] = bufout[ 6];
buffer[10] = bufout[46];
buffer[11] = bufout[14];
buffer[12] = bufout[54];
buffer[13] = bufout[22];
buffer[14] = bufout[62];
buffer[15] = bufout[30];
buffer[16] = bufout[37];
buffer[17] = bufout[ 5];
buffer[18] = bufout[45];
buffer[19] = bufout[13];
buffer[20] = bufout[53];
buffer[21] = bufout[21];
buffer[22] = bufout[61];
buffer[23] = bufout[29];
buffer[24] = bufout[36];
buffer[25] = bufout[ 4];
buffer[26] = bufout[44];
buffer[27] = bufout[12];
buffer[28] = bufout[52];
buffer[29] = bufout[20];
buffer[30] = bufout[60];
buffer[31] = bufout[28];
buffer[32] = bufout[35];
buffer[33] = bufout[ 3];
buffer[34] = bufout[43];
buffer[35] = bufout[11];
buffer[36] = bufout[51];
buffer[37] = bufout[19];
buffer[38] = bufout[59];
buffer[39] = bufout[27];
buffer[40] = bufout[34];
buffer[41] = bufout[ 2];
buffer[42] = bufout[42];
buffer[43] = bufout[10];
buffer[44] = bufout[50];
buffer[45] = bufout[18];
buffer[46] = bufout[58];
buffer[47] = bufout[26];
buffer[48] = bufout[33];
buffer[49] = bufout[ 1];
buffer[50] = bufout[41];
buffer[51] = bufout[ 9];
buffer[52] = bufout[49];
buffer[53] = bufout[17];
buffer[54] = bufout[57];
buffer[55] = bufout[25];
buffer[56] = bufout[32];
buffer[57] = bufout[ 0];
buffer[58] = bufout[40];
buffer[59] = bufout[ 8];
buffer[60] = bufout[48];
buffer[61] = bufout[16];
buffer[62] = bufout[56];
buffer[63] = bufout[24];
j = 0;
for (i = 0; i < 8; i++) {
*(dest + i) = 0x00;
for (k = 0; k < 7; k++)
*(dest + i) = ((*(dest + i)) + buffer[j+k]) * 2;
*(dest + i) = *(dest + i) + buffer[j+7];
j += 8;
}
有的话 我试试反编译把它转成C#的
不然不知道这么弄了
int GetCVN(char *OriStr,char *result)
{
// memset(OriStr,0,sizeof(OriStr));
// sprintf(OriStr,"%s","41234567890123458701111");
unsigned char operstr[9];
unsigned char uTmp[9];
char OperOri[32+1];
char szBlock1[16+1];
char szBlock2[16+1];
char buf[16+1];
char szResultA[16+1];
char szResultB[16+1];
unsigned long enkA[48], dekB[48];
int len=0;
int i=0,j=0,k=0;//第一步生成数据源,并扩展数据源为32位10进制数
memset(OperOri,0,sizeof(OperOri));
len=strlen(OriStr);
sprintf(OperOri,"%s",OriStr);
sprintf(OperOri+len,"%*.0*d",32-len,32-len,0);
log("第一步:数据源=[%s]\n",OperOri);
//第三步设置block1,block2
memset(szBlock1,0,sizeof(szBlock1));
memset(szBlock2,0,sizeof(szBlock2));
sprintf(szBlock1,"%16.16s",OperOri);
sprintf(szBlock2,"%16.16s",OperOri+16);
log("第三步:Block1=[%s]\n\tBlock2=[%s]\n",szBlock1,szBlock2);//第四步用KeyA对Block1加密
memset(buf,0,sizeof(buf));
memset(operstr,0,sizeof(operstr));
sprintf(buf,"%16.16s",szBlock1);
log("buf=[%s]\n",buf);
asc_to_bcd(buf,16,(char *)operstr);
log("operstr=[%s]\n",operstr);
deskey(KeyA, EN0, enkA);
deskey(KeyB, DE1, dekB); memset(uTmp,0,sizeof(uTmp));
desalgo (operstr,8,uTmp, enkA);// cDes desA(KeyA);
// log("实例des成功......\n");
// Sun_Des desA(KeyA);
// des.Sun_Encrypt((unsigned char *)buf,16);
// desA.Sun_Encrypt(operstr,8);
// desA.Encrypt(operstr,8);
memset(szResultA,0,sizeof(szResultA));
// memset(operstr,0,sizeof
memcpy(operstr,uTmp,8);// bcd_to_asc((char *)buf,16,szResultA);
bcd_to_asc((char *)operstr,16,szResultA);
log("第四步:用KeyA对Block1加密=[%s],buf=[%s]\n",szResultA,(char *)operstr);//第五步:用Block1的加密结果与Block2异或,在用KeyA加密
memset(szResultB,0,sizeof(szResultB));
memset(buf,0,sizeof(buf));
asc_to_bcd(szBlock2,16,buf); for(i=0; i<8; i++)
operstr[i] ^= buf[i];
bcd_to_asc((char *)operstr,16,szResultB);
log("第五步:Block1加密结果与Block2异或结果operstr=[%s],RB=[%s]\n",operstr,szResultB);
memset(uTmp,0,sizeof(uTmp));
desalgo(operstr,8,uTmp,enkA);
// desA.Encrypt(operstr,8);
// desA.Sun_Encrypt(operstr,8);
memset(szResultB,0,sizeof(szResultB));
memcpy(operstr,uTmp,8);
bcd_to_asc((char *)operstr,16,szResultB);
log("\t\t用KeyA加密后的结果:=[%s]\n",szResultB);
//第六步:用KeyB解密
memset(uTmp,0,sizeof(uTmp));
desalgo(operstr,8,uTmp,dekB);
// cDes desB(KeyB);
// desB.Decrypt(operstr,8);
// Sun_Des desB(KeyB)
// desB.Sun_Decrypt(operstr,8); memset(szResultB,0,sizeof(szResultB));
memcpy(operstr,uTmp,8);
bcd_to_asc((char *)operstr,16,szResultB);
log("第六步:用KeyB解密后的结果为=[%s]\n",szResultB);//第七步:用KeyA加密
memset(uTmp,0,sizeof(uTmp));
desalgo(operstr,8,uTmp,enkA);
// desA.Encrypt(operstr,8);
// desA.Sun_Encrypt(operstr,8); memset(szResultB,0,sizeof(szResultB));
memcpy(operstr,uTmp,8);
bcd_to_asc((char *)operstr,16,szResultB);
log("第七步:用KeyA加密后的结果为=[%s]\n",szResultB);//第八步:抽出结果中的数字
memset(szResultA,0,sizeof(szResultA));
memset(buf,0,sizeof(buf));
for(i=0;i<16;i++)
{
if(isdigit(szResultB[i]))
{
szResultA[j]=szResultB[i];
j++;
}
else
{
buf[k]=szResultB[i];
k++;
}
}
log("第八步:抽出结果中的数字=[%s]\n",szResultA);//第九步:抽出结果中的字符,减10后,连接到第八步的结果之后
log("第九步:抽出结果中的字符=[%s]\n",buf);
memset(OperOri,0,sizeof(OperOri)); len=strlen(buf);
for(i=0;i<len;i++)
{
switch(buf[i])
{
case 'A':
j=10;
break;
case 'B':
j=11;
break;
case 'C':
j=12;
break;
case 'D':
j=13;
break;
case 'E':
j=14;
break;
case 'F':
j=15;
break;
default:
return -1;
}
sprintf(OperOri+i,"%d",j-10);
}
log("\t\t减10后的数字串是:=[%s]\n",OperOri);
strcat(szResultA,OperOri);
log("\t\t连接到地八步后的串是:=[%s]\n",szResultA);//第十部取结果串的最左边三位为CVN码
memset(result,0,sizeof(result));
sprintf(result,"%3.3s",szResultA);
log("第十步:CVN=[%s]\n",result);
return 1;}
int CARD::Get_Cvn(char *kstr,char *mdte,char *mfdm)
{
/*************************************************************
*卡号(kstr)+有效期(mdte)+服务代码(mfdm)
**************************************************************/
unsigned char KeyA[8]={0xd3,0x1a,0xe7,0x29,0x5b,0x48,0xcf,0x06};
unsigned char KeyB[8]={0x2b,0x62,0x13,0x7d,0x0b,0xfb,0x9a,0x68};
//logfile->Write("zgy bb:kstr=%19.19s,mdte=%4.4s,mfdm=%3.3s\n",kstr,mdte,mfdm);
//logfile->Write("zgy bb:kstr=%s,mdte=%s,mfdm=%s\n",kstr,mdte,mfdm); cDes desA (KeyA);
cDes desB (KeyB);
unsigned char data[8],data1[8],tmstr1[5],result[17]; char mstr[33],bstr[129],tmstr[3];
char block1[17],block2[17];
int tlen,i,len,l;
char t1,t2,t3[2];
char cstr[2],cestr[2],tnum[17],cnum[17],tstr[17],testr[17];
char rnum[17];
char cvn[4]; tlen=32; /**************************************************************
*将卡号+有效期+服务代码扩展到128位数据源(不足128右补二进制0)
**************************************************************/
memset(mstr,'\0',sizeof(mstr)); /*nTrim(kstr);
nTrim(mdte);
nTrim(mfdm);*/
strcpy(kstr,trim(kstr));
strcpy(mdte,trim(mdte));
strcpy(mfdm,trim(mfdm)); strcpy(mstr,kstr);
strcat(mstr,mdte);
strcat(mstr,mfdm);
for (i=strlen(mstr);i<tlen;i++)
{
strcat(mstr,"0");
} /**************************************************************
*将128位数据源分成两个64位的数据块。最左边64位为block1,最右边
*64位为block2
**************************************************************/
memset(block1,'\0',sizeof(block1));
memset(block2,'\0',sizeof(block2)); strncpy(block1,mstr,16); strncpy(block2,mstr+16,16); /**************************************************************
*block1转换为8字节的十六进制字符串data
**************************************************************/
memset(data,'\0',sizeof(data));
memset(tmstr,'\0',sizeof(tmstr));
memset(tmstr1,'\0',sizeof(tmstr1)); len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,block1+len,2);
asc_to_bcd((unsigned char *)tmstr1,(unsigned char *)tmstr,2,0);
data[i]=tmstr1[0];
len=len+2;
} /**************************************************************
*将data数据用KeyA加密,结果为result
**************************************************************/
memset(result,'\0',sizeof(result)); //des(data,result,KeyA,1);
memcpy(result, data, sizeof(data));
desA.Encrypt(result);/*
printf("%02x",result[0]);
printf("%02x",result[1]);
printf("%02x",result[2]);
printf("%02x",result[3]);
printf("%02x",result[4]);
printf("%02x",result[5]);
printf("%02x",result[6]);
printf("%02x\n",result[7]);
*/ /**************************************************************
*将result,转换为8字节的字符串tstr
**************************************************************/
memset(tstr,'\0',sizeof(tstr));
memset(cstr,'\0',sizeof(cstr)); for(i=0;i<8;i++)
{
sprintf(cstr,"%02x", result[i]);
strcat(tstr,cstr);
} /**************************************************************
*将tstr同block2进行异或,结果为testr
**************************************************************/
memset(testr,'\0',sizeof(testr));
memset(cestr,'\0',sizeof(cestr)); for(i=0;i<16;i++)
{
if (tstr[i]>='a' || tstr[i]>='A')
t1=tstr[i]-'a'+10;
else
t1=tstr[i]-'0';
if (block2[i]>='a' || block2[i]>='A')
t2=block2[i]-'a'+10;
else
t2=block2[i]-'0';
sprintf(cestr,"%x", t1^t2);
strcat(testr,cestr);
} /**************************************************************
*testr转换为8字节的十六进制字符串data1
**************************************************************/
memset(data1,'\0',sizeof(data1));
memset(tmstr,'\0',sizeof(tmstr));
memset(tmstr1,'\0',sizeof(tmstr1));
len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,testr+len,2);
asc_to_bcd((unsigned char *)tmstr1,(unsigned char *)tmstr,2,0);
data1[i]=tmstr1[0];
len=len+2;
} /**************************************************************
*将data1数据用KeyA加密,结果为result
**************************************************************/
memset(result,'\0',sizeof(result)); //des(data1,result,KeyA,1);
memcpy(result, data1, sizeof(data1));
desA.Encrypt(result);/*
printf("%02x",result[0]);
printf("%02x",result[1]);
printf("%02x",result[2]);
printf("%02x",result[3]);
printf("%02x",result[4]);
printf("%02x",result[5]);
printf("%02x",result[6]);
printf("%02x\n",result[7]);
*/ /**************************************************************
*将result数据用KeyB解密,结果为result
**************************************************************/
//des(result,result,KeyB,0);
//memcpy(result, result, sizeof(result));
desB.Decrypt(result);/*
printf("%02x",result[0]);
printf("%02x",result[1]);
printf("%02x",result[2]);
printf("%02x",result[3]);
printf("%02x",result[4]);
printf("%02x",result[5]);
printf("%02x",result[6]);
printf("%02x\n",result[7]);
*/ /**************************************************************
*将result数据用KeyA加密,结果为result
**************************************************************/
//des(result,result,KeyA,1);
//memcpy(result, result, sizeof(result));
desA.Encrypt(result);/*
printf("%02x",result[0]);
printf("%02x",result[1]);
printf("%02x",result[2]);
printf("%02x",result[3]);
printf("%02x",result[4]);
printf("%02x",result[5]);
printf("%02x",result[6]);
printf("%02x\n",result[7]);
*/ /**************************************************************
*将result转换为8字节十六进制数据tstr
**************************************************************/
memset(cstr,'\0',sizeof(cstr));
memset(tstr,'\0',sizeof(tstr)); for(i=0;i<8;i++)
{
sprintf(cstr,"%02x", result[i]);
strcat(tstr,cstr);
} /**************************************************************
*将tstr中的数字提取出来,结果tnum;
*将tstr中的字符抽出,减10后将余数组成一组数字cnum,放在tnum后
**************************************************************/
memset(tnum,'\0',sizeof(tnum));
memset(cnum,'\0',sizeof(cnum)); for(i=0;i<16;i++)
{
if (tstr[i]>='0' && tstr[i]<='9')
{
sprintf(t3,"%c",tstr[i] );
strcat(tnum,t3);
}
if ((tstr[i]>='a' && tstr[i]<='f') ||
(tstr[i]>='A' && tstr[i]<='F'))
{
sprintf(t3,"%d",tstr[i]-'a');
strcat(cnum,t3);
}
} memset(rnum,'\0',sizeof(rnum));
strcpy(rnum,tnum);
strcat(rnum,cnum); memset(cvn,'\0',sizeof(cvn)); strncpy(cvn,rnum,3); strcpy(Tcvn,cvn);
//logfile->Write("Tcvn=%s,cvn=%s\n",Tcvn,cvn); return 0;
}
我把代码拷贝到c++项目里编译一下错误一大堆,不知道怎么改。
你还是再发个帖子请个会c++的进来这边看把。
结果:B76A DDCE 71CC C6BE 16位我加密出来的结果却是24位
private void Button1_Click(object sender, System.EventArgs e)
{
//第一步:合并字符串(将卡号+有效期+服务代码)
string str = "62242196010000049944912120"; //第二步:补齐128位二进制零
byte[] binaryBytes = System.Text.Encoding.Unicode.GetBytes(str);
//以UTF8编码方式,把字节数组还原为字符串。
string newText = System.Text.Encoding.Unicode.GetString( binaryBytes );
//向右补齐128位二进制零
while(newText.Length<32)
{
newText=newText+"0";
} //第三步:/**************************************************************/
/*将128位数据源分成两个64位的数据块。最左边64位为block1,最右边*/
/*64位为block2**************************************************/
string Block1=newText.Substring(0,16);//最左边的64位为Block1
string Block2=newText.Substring(16);//最右边的64位为Block2
//第四步:。。
}
将data数据用KeyA加密,结果为result
将result,转换为8字节的字符串tstr
参照C代码
/**************************************************************
*block1转换为8字节的十六进制字符串data
**************************************************************/
memset(data,'\0',sizeof(data));//设置s中的所有字节为ch, s数组的大小由n给定
memset(tmstr,'\0',sizeof(tmstr));
memset(tmstr1,'\0',sizeof(tmstr1)); len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,block1+len,2);
asc_to_bcd((unsigned char *)tmstr1,(unsigned char *)tmstr,2,0);
data[i]=tmstr1[0];
len=len+2;
} /**************************************************************
*将data数据用KeyA加密,结果为result
**************************************************************/
memset(result,'\0',sizeof(result)); memcpy(result, data, sizeof(data));
desA.Encrypt(result);
/**************************************************************
*将result,转换为8字节的字符串tstr
**************************************************************/
memset(tstr,'\0',sizeof(tstr));
memset(cstr,'\0',sizeof(cstr)); for(i=0;i<8;i++)
{
sprintf(cstr,"%02x", result[i]);
strcat(tstr,cstr);
}
(string)block1转换为16进制为:36323234323139363031303030303034 采用密钥:0123456789ABCDEF进行3DES加密结果为q7DTyQsmu5NQ5L6riPCnVDx6GXsYORFzHhJZA2pjHjyrulxKIzP4Qw==
(int)block1转换为16进制为:161CE50E525644 采用密钥:0123456789ABCDEF进行3DES加密结果为5DQAlwA3AH8rXp4EntS8vg==结果都跟你那个不一样呀
len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,block1+len,2);
asc_to_bcd((unsigned char *)tmstr1,(unsigned char *)tmstr,2,0);
data[i]=tmstr1[0];
len=len+2;
}//C#==================
string [] data = new string[8];
int j = 0;
for (int i = 0; i < 8; i++)
{
data[i] = String.Format(CultureInfo.InvariantCulture, "{0:X2}", Convert.ToInt32(Block1.Substring(j, 2)));
j += 2;
}==========加密============
desA.Encrypt(result);
怎么加密都不对 不会翻译这里。
=========================
//C++======================
for(i=0;i<8;i++)
{
sprintf(cstr,"%02x", result[i]);
strcat(tstr,cstr);
}
//C#======================
string tstr = "";
for(i=0;i<8;i++)\
{
tstr += result[i].ToString("X2");
}
block1转换为8字节的十六进制字符串data,我刚在看这里是我把字符串转成十六进制在截取8位还是怎么算的。
*block1转换为8字节的十六进制字符串data
**************************************************************/
memset(data,'\0',sizeof(data));//设置s中的所有字节为ch, s数组的大小由n给定
memset(tmstr,'\0',sizeof(tmstr));
memset(tmstr1,'\0',sizeof(tmstr1)); len=0;
for(i=0;i<8;i++)
{
strncpy(tmstr,block1+len,2); // 假如:block1 =4123456789012345,第一次循环截取 41,第二次截取23、45、67类推。
asc_to_bcd((unsigned char *)tmstr1,(unsigned char *)tmstr,2,0);//十六进制字符串data,上面注释中这样写到,应该是将41(string还是int就不知道了)转换成16进制。
data[i]=tmstr1[0]; // 把转换后的结果给data数组, data是string[]还是byte[]也不知道
len=len+2;
}
不如你直接问一下需求方
1.是否采用3DES加密,字符串的编码有什么规定,不同编码加密出来的东西也不一样
2.如果值是 4123456789012345 KEY是:0123456789ABCDEF 加密出来的数据是多少?(可以有个正确参照)、
3. 是直接拿4123456789012345 进行加密还是处理后的数据进行的DES加密,如果是处理后的那么处理的需求是什么(如上面的什么转换成8位16进制)。
这几个问题搞清楚了就没什么难度了