openFileDialog控件的选中文件的返回路径怎么得到？

Question

OpenFileDialog.FileName 属性可以得到文件路径名在属性里可以设置过虑条件

Answer 1

[C#] 
protected void button1_Click(object sender, System.EventArgs e)
{
    Stream myStream;
    OpenFileDialog openFileDialog1 = new OpenFileDialog();    openFileDialog1.InitialDirectory = "c:\\" ;
    openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ;
    openFileDialog1.FilterIndex = 2 ;
    openFileDialog1.RestoreDirectory = true ;    if(openFileDialog1.ShowDialog() == DialogResult.OK)
    {
        if((myStream = openFileDialog1.OpenFile())!= null)
        {
            // Insert code to read the stream here.
            myStream.Close();
        }
    }
}其中的openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ;