求教两个关于GDI+的高级问题

关于使用GDI＋的绘图问题
我给你一个函数，是使用纯GDI+画出的曲线表格，应该能解决你的画图问题
//»æÖÆ±í¸ñ£¨ÕÛÏßÍ¼£©
public virtual void DrawChart(System.Data.DataSet ds,string strName,ref System.IO.MemoryStream objIMG)
{
System.Drawing.Bitmap objBitbmp = new Bitmap(iIMGWith,iIMGHight);
System.IO.MemoryStream objIMGstream = new MemoryStream();
try
{
System.Drawing.Graphics MyGraphic = Graphics.FromImage(objBitbmp);
System.Drawing.Pen myPen = new Pen(new SolidBrush(Color.Blue));
System.Drawing.Pen BackPen = new Pen(new SolidBrush(Color.Black),2);
System.Drawing.Pen FloatPen = new Pen(new SolidBrush(Color.Red),1);

//¶¨Òå»±ÊÎªÐéÏß
float[] myfloat = {3,3};
FloatPen.DashPattern = myfloat;
System.Drawing.Point Xpoint = new Point(0,0);
System.Drawing.Point Ypoint = new Point(0,0);
string strColName; //»æÖÆ±³¾°Í¸Ã÷
MyGraphic.FillRectangle(new SolidBrush(Color.FromArgb(255,Color.Yellow)),0,0,300,200); //µÃµ½Êý¾ÝÓÐ¶àÉÙÁÐ
int iCount = ds.Tables[strName].Columns.Count;
int iMaxValue = 0;
int i,iTemp;
string iTempNum;
int ix = 20;
int iy = iIMGHight - 20;
Point[] objPoint = new Point[iCount]; //³õÊ¼»¯×ø±êÏµ
PointF XpointS = new PointF(ix,iy);
PointF XpointE = new PointF(ix,20);
PointF YpointS = new PointF(ix,iy);
PointF YpointE = new PointF(iIMGWith - ix,iy);

if (ds.Tables[strName].Rows.Count < 1)
{
throw new Exception("ÄúµÄÊý¾Ý¼¯²»´æÔÚ¡£");
}
//²éÕÒ×î´óµÄÊý¾Ý
for(i = 0;i<=iCount - 1;i++)
{
iTempNum = ds.Tables[strName].Rows[0][i].ToString();
if(iMaxValue <= Convert.ToInt32(iTempNum))
{
iMaxValue = Convert.ToInt32(iTempNum);
}
}
//¿ªÊ¼±éÀúÊý¾ÝµãÕó,½«ÕÛÏßµÄµãÕó»æÖÆµ½Í¼ÏñÖÐ
for(i = 0;i<=iCount - 1;i++)
{
//¼ÆËã½«Êý¾Ý»æÖÆµ½Í¼Æ¬ÖÐµÄ±ÈÀý
iTemp = (int)ds.Tables[strName].Rows[0][i];
iy = (int)(((float)iTemp/(float)iMaxValue) * 160);
if(iy == 0)
{
iy = 20;
}
objPoint[i].X = ix;
objPoint[i].Y = iIMGHight - 20 - iy;
ix = ix + 50; //»æÖÆÐéÏß£¬±êÃ÷×ø±ê
Xpoint.X = objPoint[i].X;
Xpoint.Y = iIMGHight - 20;
MyGraphic.DrawLine(FloatPen,objPoint[i],Xpoint);
Ypoint.X = 20;
Ypoint.Y = objPoint[i].Y;
MyGraphic.DrawLine(FloatPen,objPoint[i],Ypoint);
MyGraphic.DrawString(ds.Tables[strName].Rows[0][i].ToString(),new Font("ËÎÌå",7),new SolidBrush(Color.Black),2,Ypoint.Y);
//µÃµ½ÁÐÃû
strColName = ds.Tables[strName].Columns[i].ColumnName;
strColName = strColName.Substring(strColName.Length - 5,5);
MyGraphic.DrawString(strColName,new Font("ËÎÌå",7),new SolidBrush(Color.Black),Xpoint.X,Xpoint.Y); }

//»æÖÆÇúÏß£¬x,yÖáµÄÏß¶Î
MyGraphic.DrawLine(BackPen,XpointS,XpointE);
MyGraphic.DrawLine(BackPen,YpointS,YpointE);
MyGraphic.DrawLine(BackPen,XpointE.X-4,XpointE.Y,XpointE.X,XpointE.Y-8);    //»æÖÆ¼ýÍ·
MyGraphic.DrawLine(BackPen,XpointE.X+4,XpointE.Y,XpointE.X,XpointE.Y-8);    //»æÖÆ¼ýÍ·
MyGraphic.DrawLine(BackPen,XpointE.X-4,XpointE.Y,XpointE.X+4,XpointE.Y);    //»æÖÆ¼ýÍ·
MyGraphic.DrawString(strXDesc,new Font("ËÎÌå",7),new SolidBrush(Color.Red),XpointE.X,0);   //»æÖÆ×ø±êÎÄ×Ö
MyGraphic.DrawLine(BackPen,YpointE.X,YpointE.Y-4,YpointE.X+8,YpointE.Y);    //»æÖÆ¼ýÍ·
MyGraphic.DrawLine(BackPen,YpointE.X,YpointE.Y+4,YpointE.X+8,YpointE.Y);    //»æÖÆ¼ýÍ·
MyGraphic.DrawLine(BackPen,YpointE.X,YpointE.Y-4,YpointE.X,YpointE.Y+4);    //»æÖÆ¼ýÍ·
                MyGraphic.DrawString(strYDesc,new Font("ËÎÌå",7),new SolidBrush(Color.Red),YpointE.X,YpointE.Y);   //»æÖÆ×ø±êÎÄ×Ö //»æÖÆÇúÏß
if(objPoint.Length > 1)
{
MyGraphic.DrawLines(myPen,objPoint);
}
else
{

}

objBitbmp.Save(objIMGstream,ImageFormat.Gif);
objIMGstream.Position = 0;
objIMG = objIMGstream;
}
catch(System.Exception ex)
{
strError = ex.Message.ToString();
objIMG = objIMGstream;
}
finally
{
objBitbmp.Dispose();
}
}关于在图形上判断焦点的动作，我是这样坐的。
当你画图的时候会有一个point[]数组。把这个数组保存下来，在MouseDown事件中判断是否鼠标属于这个point,然后比较是否存在于point[]，如果存在，在图层上绘制一个正方形的小实体块。标明位置。
至于上下文菜单，你可以定义指定的点弹出指定右键菜单。
我就是用这种方法写了一个公共类，现在使用的还不错。

解决方案 »

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首先感谢free_eyes的帮助，焦点问题解决得不是很理想，最好象Flash MX那样——在工作界面绘出图形后，可以点选并能够很直观、很方便地用右键操作。    再等两天，看看还有没有更好的解决办法，11号晚结贴，再次感谢free_eyes。