xml 解析啊，求大侠们帮忙。。

Question

<diffgr:diffgram xmlns:msdata="um:schemas-microsoft-com:xml-msdata" xmlns:diffgr="um:schemas-microsoft-com:xml-msdata"/>
-<SwOwner xmlns="">
-<SwOwner diffgr:id="SwOwner1" msdata:rowOrder="0">
<ID>32323</ID>
<NAME>小羊</NAME>
<TYPESOFCERTIFICATES>身份证</TYPESOFCERTIFICATES>
<NUMBERQFCREDENTIAL>2342342323233</NUMBERQFCREDENTIAL>
<SELLERORBUYER>0</SELLERORBUYER>
<SLBH>201305030151</SLBH>
</SwOwner>
-<SwOwner diffgr:id="SwOwner2" msdata:rowOrder="0">
<ID>32323</ID>
<NAME>小羊</NAME>
<TYPESOFCERTIFICATES>身份证</TYPESOFCERTIFICATES>
<NUMBERQFCREDENTIAL>2342342323233</NUMBERQFCREDENTIAL>
<SELLERORBUYER>0</SELLERORBUYER>
<SLBH>201305030151</SLBH>
</SwOwner>
-<SwOwner diffgr:id="SwOwner3" msdata:rowOrder="0">
<ID>32323</ID>
<NAME>小羊</NAME>
<TYPESOFCERTIFICATES>身份证</TYPESOFCERTIFICATES>
<NUMBERQFCREDENTIAL>2342342323233</NUMBERQFCREDENTIAL>
<SELLERORBUYER>0</SELLERORBUYER>
<SLBH>201305030151</SLBH>
</SwOwner>怎么获取里面的ID 和name啊XMLC#

Answer 1

var xml = new XmlDocument();
xml.Load(path);
foreach(XmlNode node in xml.SelectNodes("//SwOwner"))
{
    if(node.HasChildNodes)
    {
        var id = node.ChildNodes[0].InnerText;
        var name = node.ChildNodes[1].InnerText;
    }
}
Linq to xml也可以

Answer 2

说有非法字符， load 不进来啊。。

Answer 3

说有非法字符， load 不进来啊。。要么就是 跟级别上的数据无效