C#利用mutex进行多线程同步的问题

Question

多线程c#

Answer 1

using System;
using System.Threading;namespace ConsoleApplication1
{
    class Program
    {
        static Mutex mutex = new Mutex();
        static number num = new number();
        class number
        {
            public int a = 0;
        }
        class Plus
        {
            public void plus()
            {
                while (true)
                {
                    mutex.WaitOne();
                    num.a++;
                    Console.WriteLine("OK");
                    mutex.ReleaseMutex();
                    Thread.Sleep(500);
                }
            }
        }
        class Show
        {
            public void show()
            {
                while (true)
                {
                    mutex.WaitOne();
                    Console.WriteLine(num.a);
                    mutex.ReleaseMutex();
                    Thread.Sleep(500);
                }
            }
        }
        static void Main(string[] args)
        {
            Plus plus = new Plus();
            Show show = new Show();
            Thread thread1 = new Thread(new ThreadStart(plus.plus));
            Thread thread2 = new Thread(new ThreadStart(show.show));
            thread1.Start();
            thread2.Start();
            new ManualResetEvent(false).WaitOne();      //按Ctrl+C退出
        }    }
}

Answer 2

实际上，如果你把第二个  Thread.Sleep(500); 语句删除掉，你会发现这个程序输出的是垃圾信息（根本没有保持现在的输出序列）！因此，我不知道你这个程序是从哪里抄来的，但是要告诉你，稍微变换一下测试方法，你应该发现哪些代码是垃圾。不要轻信一些博客、培训师所给你的代码。你要自己动手测试！

Answer 3

这样的同步才是正常的using System;
using System.Threading;namespace ConsoleApplication1
{
    class Program
    {
        static AutoResetEvent 生产 = new AutoResetEvent(true);
        static AutoResetEvent 使用 = new AutoResetEvent(false);
        static number num = new number();        class number
        {
            public int a = 0;
        }        class Plus
        {
            public void plus()
            {
                while (true)
                {
                    生产.WaitOne();
                    num.a++;
                    Console.WriteLine("OK");
                    使用.Set();
                    Thread.Sleep(500);
                }
            }
        }        class Show
        {
            public void show()
            {
                while (true)
                {
                    使用.WaitOne();
                    Console.WriteLine(num.a);
                    生产.Set();
                }
            }
        }
        static void Main(string[] args)
        {
            Plus plus = new Plus();
            Show show = new Show();
            Thread thread1 = new Thread(new ThreadStart(plus.plus));
            Thread thread2 = new Thread(new ThreadStart(show.show));
            thread1.Start();
            thread2.Start();
            new ManualResetEvent(false).WaitOne();      //按Ctrl+C退出
        }    }
}