急求正则表达式处理字符串

Question

string result = Regex.Replace("内容", @"([\w]*?,[\w]+)", "\"$1\"");

Answer 1

str=Regex.Replace(str,@"\w+,\w+","'$0'");

Answer 2

不符合啊 "Time:2013-11-11 10:54.41\r\nPoint\tZ\t\r\n{X=-147, Y=0}\t1660.9\t\r\n{X=-141.12, Y=0}\t1660.9\t\r\n{X=-135.24, Y=0}\t1660.9\t\r\n"对这个字符串 希望匹配后能变成
"Time:2013-11-11 10:54.41
Point Z
'{X=-147, Y=0} '1660.9
'{X=-141.12, Y=0} '1660.9
'{X=-135.24, Y=0} '1660.9"

Answer 3

还是不行我是想把一个字符串
"Time:2013-11-11 10:54.41\r\nPoint\tZ\t\r\n{X=-147, Y=0}\t1660.9\t\r\n{X=-141.12, Y=0}\t1660.9\t\r\n{X=-135.24, Y=0}\t1660.9\t\r\n"写到CSV文件里头,这样显示唉..:
Time              2013-11-11 10:54.41
Point             Z
{X=-147, Y=0}     1660.9
{X=-141.12, Y=0}  1660.9
{X=-135.24, Y=0}  1660.9

Answer 4

不符合啊 "Time:2013-11-11 10:54.41\r\nPoint\tZ\t\r\n{X=-147, Y=0}\t1660.9\t\r\n{X=-141.12, Y=0}\t1660.9\t\r\n{X=-135.24, Y=0}\t1660.9\t\r\n"对这个字符串 希望匹配后能变成
"Time:2013-11-11 10:54.41
Point Z
'{X=-147, Y=0} '1660.9
'{X=-141.12, Y=0} '1660.9
'{X=-135.24, Y=0} '1660.9"
string result = Regex.Replace("内容", @"{.*?,[^}]+?}", "'$0'");

Answer 5

不符合啊 "Time:2013-11-11 10:54.41\r\nPoint\tZ\t\r\n{X=-147, Y=0}\t1660.9\t\r\n{X=-141.12, Y=0}\t1660.9\t\r\n{X=-135.24, Y=0}\t1660.9\t\r\n"对这个字符串 希望匹配后能变成
"Time:2013-11-11 10:54.41
Point Z
'{X=-147, Y=0} '1660.9
'{X=-141.12, Y=0} '1660.9
'{X=-135.24, Y=0} '1660.9"
string result = Regex.Replace("内容", @"{.*?,[^}]+?}", "'$0'");如果原数据没有{和}呢?

Answer 6

不符合啊 "Time:2013-11-11 10:54.41\r\nPoint\tZ\t\r\n{X=-147, Y=0}\t1660.9\t\r\n{X=-141.12, Y=0}\t1660.9\t\r\n{X=-135.24, Y=0}\t1660.9\t\r\n"对这个字符串 希望匹配后能变成
"Time:2013-11-11 10:54.41
Point Z
'{X=-147, Y=0} '1660.9
'{X=-141.12, Y=0} '1660.9
'{X=-135.24, Y=0} '1660.9"
string result = Regex.Replace("内容", @"{.*?,[^}]+?}", "'$0'");如果原数据没有{和}呢?
string result = Regex.Replace("内容", @"\S+,[ ]\S+", "'$0'");