How to catch the Exception when using BeginInvoker, Give me some tips, thank you(Just use English to attract more attentions)

Question

Divider.csusing System;
using System.Linq;
using System.Web;
using System.Xml.Linq;
using System.Threading;
using System.Runtime.Remoting.Messaging;public delegate int Comuter(int a, int b);public delegate void DivCompleteHandler(object sender, DivCompleteEventArgs e);
public class Divider
{
    public event DivCompleteHandler OnDivComplete;
    public Divider()
    {    }    public int Div(int a, int b)
    {
        Thread.Sleep(5000);        try
        {
            return a / b;
        }
        catch (DivideByZeroException e)
        {
            throw e;
        }
    }    public void DivAsyn(int a, int b)
    {
        Comuter computer = new Comuter(this.Div);
        computer.BeginInvoke(a, b, new AsyncCallback(Response), null);
    }    void Response(IAsyncResult result)
    {
        try
        {
            Comuter computer = ((AsyncResult)result).AsyncDelegate as Comuter;            if (null != computer)
            {
                int consult = computer.EndInvoke(result);
                OnDivComplete(this, new DivCompleteEventArgs(consult, null, false, null));
            }
        }
        catch (DivideByZeroException e)
        {
            OnDivComplete(this, new DivCompleteEventArgs(0, e, true, null));
        }
        catch (Exception e)
        {
            OnDivComplete(this, new DivCompleteEventArgs(0, e, true, null));
        }    }
}

Answer 1

MainFrame.csusing System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Reflection;
namespace DividerForm
{
    
    internal delegate void SetResult(string content);
    
    public partial class MainFrame : Form
    {
        public MainFrame()
        {
            InitializeComponent();
        }        private void btnDivide_Click(object sender, EventArgs e)
        {
            int num1 = Convert.ToInt32(this.tbNum1.Text);
            int num2 = Convert.ToInt32(this.tbNum2.Text);            Divider divider = new Divider();
            divider.OnDivComplete+=new DivCompleteHandler(GetDivResultComplete);            divider.DivAsyn(num1, num2);        }        private void MainFrame_Load(object sender, EventArgs e)
        {        }        public void SetResultText(string content)
        {
            this.result.Text=content;
        }        private void GetDivResultComplete(object sender, DivCompleteEventArgs e)
        {            if (!e.Cancelled)
            {
                string content = e.Result.ToString();
                SetResult sr = new SetResult(SetResultText);
                this.result.Invoke(sr, new string[] { content });
            }
            else
            {
                MessageBox.Show(e.Error.Message);
            }        }
    }
}

Answer 2

PS:没有发生异常的适合，我的程序是可以工作的，当除数为0的时候，异常抓不到，针对BeginInvoke，该怎么抓异常呢

Answer 3

一般来说跨线程设计时不要通过Exception机制在线程间传递信息。

Answer 4

如果lz确实想要这个feature，建议lz看看remoting中对异常的处理。