using System.IO //读写文件需要的再看你具体读什么文件了,如果是xml,那么还需要using System.Xml

解决方案 »

  1.   

    using System;
    using System.Collections.Generic;
    using System.ComponentModel;
    using System.Data;
    using System.Drawing;
    using System.Text;
    using System.Windows.Forms;
    using System.IO;namespace WindowsAppTest
    {
        public partial class Form1 : Form
        {
            public Form1()
            {
                InitializeComponent();
            }        private void button1_Click(object sender, EventArgs e)
            {
                StreamWriter sw;
                if (!File.Exists(@"c:\Test1.txt"))
                {
                    sw = File.CreateText(@"c:\Test1.txt");
                    sw.WriteLine("-----------------------------------------------------------------");
                    sw.WriteLine(this.textBox1.Text);
                    sw.WriteLine(this.textBox2.Text);
                    sw.WriteLine(System.DateTime.Now);
                    sw.Close();
                }
                else
                {
                    sw = File.AppendText(@"c:\Test1.txt");
                    sw.WriteLine("-----------------------------------------------------------------");
                    sw.WriteLine(this.textBox1.Text);
                    sw.WriteLine(this.textBox2.Text);
                    sw.WriteLine(System.DateTime.Now);
                    sw.Close();
                }
                this.button1.Text = "OK";
            }
        }
    }应该很容易看懂,不做说明了.希望能够抛砖引玉:)
      

  2.   

    要引用的就是USING SYSTEM.IO;红色字体标明的
      

  3.   

    如果仅仅是打开, 可以用string path = "test.txt";
    System.Diagnostics.Process.Start(path);string appPath = "C:\\Windows\\Notepad.exe";
    System.Diagnostics.Process.Start(appPath);