客户用java做开发，sojo序列化和反序列化，得到的结果如下："endDt":"2012-02-18 16:33:38.155",然后我用.net做开发，这样的格式没法反序列化，错误为 <?xml version="1.0" encoding="utf-8" ?>
<string xmlns="http://tempuri.org/">{"code":500,"message":"There was an error deserializing the object of type XFFW.Model.SelectiveExaminationModel. DateTime content '2012-02-18 16:33:38.155' does not start with '\\\/Date(' and end with ')\\\/' as required for JSON.","returnvalue":null}</string> 请问碰到这样的事情怎么解决比较好
<string xmlns="http://tempuri.org/">{"code":500,"message":"There was an error deserializing the object of type XFFW.Model.SelectiveExaminationModel. DateTime content '2012-02-18 16:33:38.155' does not start with '\\\/Date(' and end with ')\\\/' as required for JSON.","returnvalue":null}</string> 请问碰到这样的事情怎么解决比较好
* DataContractJsonSerializer在System.Runtime.Serialization.Json命名空间下，
* .NET Framework 3.5包含在System.ServiceModel.Web.dll中，需要添加对其的引用；
* .NET Framework 4在System.Runtime.Serialization中。
*/ /// <summary>
/// JSON序列化
/// </summary>
public static string JsonSerializer<T>(T t)
{
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));
System.IO.MemoryStream ms = new System.IO.MemoryStream();
ser.WriteObject(ms, t);
string jsonString = System.Text.Encoding.UTF8.GetString(ms.ToArray());
ms.Close();
//替换Json的Date字符串
string p = @"\\/Date\((\d+)\+\d+\)\\/";
System.Text.RegularExpressions.MatchEvaluator matchEvaluator = new System.Text.RegularExpressions.MatchEvaluator(ConvertJsonDateToDateString);
System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(p);
jsonString = reg.Replace(jsonString, matchEvaluator);
return jsonString;
} /// <summary>
/// JSON反序列化
/// </summary>
public static T JsonDeserialize<T>(string jsonString)
{
//将"yyyy-MM-dd HH:mm:ss"格式的字符串转为"\/Date(1294499956278+0800)\/"格式
string p = @"\d{4}-\d{2}-\d{2}\s\d{2}:\d{2}:\d{2}";
System.Text.RegularExpressions.MatchEvaluator matchEvaluator = new System.Text.RegularExpressions.MatchEvaluator(ConvertDateStringToJsonDate);
System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(p);
jsonString = reg.Replace(jsonString, matchEvaluator);
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));
System.IO.MemoryStream ms = new System.IO.MemoryStream(Encoding.UTF8.GetBytes(jsonString));
T obj = (T)ser.ReadObject(ms);
return obj;
} /// <summary>
/// 将Json序列化的时间由/Date(1294499956278+0800)转为字符串
/// </summary>
private static string ConvertJsonDateToDateString(System.Text.RegularExpressions.Match m)
{
string result = string.Empty;
DateTime dt = new DateTime(1970, 1, 1);
dt = dt.AddMilliseconds(long.Parse(m.Groups[1].Value));
dt = dt.ToLocalTime();
result = dt.ToString("yyyy-MM-dd HH:mm:ss");
return result;
} /// <summary>
/// 将时间字符串转为Json时间
/// </summary>
private static string ConvertDateStringToJsonDate(System.Text.RegularExpressions.Match m)
{
string result = string.Empty;
DateTime dt = DateTime.Parse(m.Groups[0].Value);
dt = dt.ToUniversalTime();
TimeSpan ts = dt - DateTime.Parse("1970-01-01");
result = string.Format("\\/Date({0}+0800)\\/", ts.TotalMilliseconds);
return result;
}
json规范中对于日期时间没有任何标准定义，因此有好几种特殊的处理方式。.net使用的方式也是一种方言而已。你可以将得到的json转为Json.Net的JObject对象，然后直接修改其endDt元素，然后把这个JObject对象反序列化为目标对象。据说Json.net对.net内部对象的序列化/反序列化，要比.net自身包含的json处理类库的速度快多了！