提供一个算法给你! /// <summary>
        /// 在关键字库中去匹配关键字
        /// </summary>
        /// <param name="serchedString">要匹配的字符串 例:"是中国睦邻人地<关键字>地中"</param>
        /// <returns></returns>
        public static String findTheKeyWord(String serchedString)
        {
            String serch = "";
            ArrayList list = GetKeyWords();
            int n = getTheMaxStringLenght();
            string[,] key = new string[5, 2];
            int m = 0;
            for (int i = 1; i <= n; i++)
            {
                for (int j = 0; j < serchedString.Length; j++)
                {
                    if (j + i < serchedString.Length)
                    {
                        String str = serchedString.Substring(j, i);
                        for (int k = 0; k < list.Count; k++)
                        {
                            if (str.Equals(list[k].ToString()))
                            {
                                if (m < 5)
                                {
                                    serch = "<a href='http://www.taocaibao.com'>" + str + "</a>";
                                    key[m, 0] = str;
                                    key[m, 1] = serch;
                                    m++;
                                }
                            }
                        }
                    }
                }
            }
            for (int q = 0; q < key.Length / key.Rank; q++)
            {
                if (!String.IsNullOrEmpty(key[q, 0]))
                    serchedString = serchedString.Replace(key[q, 0], key[q, 1]);
            }
            return serchedString;
        }        /// <summary>
        /// 获取关键字库中关键字最大的长度
        /// </summary>
        public static int getTheMaxStringLenght()
        {
            ArrayList list = GetKeyWords();
            int p = 0;
            if (list.Count != 0)
            {
                String str = list[0].ToString();
                for (int i = 0; i < list.Count - 1; i++)
                {
                    if (list[i].ToString().Length < list[i + 1].ToString().Length)
                    {
                        p = list[i + 1].ToString().Length;
                    }
                }
            }
            return p;
        }