高手们，可否用最短的正则表达式来匹配这组数据？

Question

[[2,"\aeeaaf9 d57",40,"0.01%",46,5,41,14,"1.1500","","0.1000",0],[468," ac\asdfa53e3347f69 \34452a0\1a5927",40,"0.01%",29,0,29,11,"0.7250","","0.0250",0.15],[85," u9ed1 32253ea\ade27f69",40,"0.01%",10,2,8,8,"0.2500","","0.1250",0.3]]谢谢@！！

Answer 1

[2,"\aeeaaf9 d57",40,"0.01%",46,5,41,14,"1.1500","","0.1000",0]
[468," ac\asdfa53e3347f69 \34452a0\1a5927",40,"0.01%",29,0,29,11,"0.7250","","0.0250",0.15]
[85," u9ed1 32253ea\ade27f69",40,"0.01%",10,2,8,8,"0.2500","","0.1250",0.3]

Answer 2

string pattern = @"\[(\[[^]]*,?\],?)*\]";

Answer 3

这应该JSON解析，如果要从后台读取这些具体数据的话，还是找个JSON解析类吧http://www.cnblogs.com/xfrog/archive/2010/04/07/1706754.html

Answer 4

            string str = @"[[2,""\aeeaaf9 d57"",40,""0.01%"",46,5,41,14,""1.1500"","""",""0.1000"",0],[468,"" ac\asdfa53e3347f69 \34452a0\1a5927"",40,""0.01%"",29,0,29,11,""0.7250"","""",""0.0250"",0.15],[85,"" u9ed1 32253ea\ade27f69"",40,""0.01%"",10,2,8,8,""0.2500"","""",""0.1250"",0.3]]";
            Regex reg = new Regex(@"(""?)([^\[\],""]+)\1");
            foreach (Match m in reg.Matches(str))
                Console.WriteLine(m.Groups[2].Value);
/*
2
\aeeaaf9 d57
40
0.01%
46
5
41
14
1.1500
0.1000
0
468
 ac\asdfa53e3347f69 \34452a0\1a5927
40
0.01%
29
0
29
11
0.7250
0.0250
0.15
85
 u9ed1 32253ea\ade27f69
40
0.01%
10
2
8
8
0.2500
0.1250
0.3
*/

Answer 5

糊涂了，正则改下
Regex reg = new Regex(@"[^\[\],""]+");

Answer 6

如果双引号之间有逗号（  [123,“ asdf  ,  a3w ,  asf ”, 546 , ...... ]   ）就不太合适了