tcpclient类post数据并获取返回结果的问题

Question

代码如下：TcpClient tcpClient = new TcpClient();
            Uri URI = new Uri("http://192.168.18.66/getData");
            tcpClient.Connect(URI.Host, URI.Port);
            NetworkStream netStream = tcpClient.GetStream();
            if (netStream.CanWrite)
            {
                string msg = "name=aabb11";
                StringBuilder sb = new StringBuilder();
                sb.Append("POST " + URI.PathAndQuery + " HTTP/1.0\r\n");
                sb.Append("Host: " + URI.Host + "\r\n");
                sb.Append("Content-Type: application/x-www-form-urlencoded\r\n");
                sb.Append("Content-Length: " + Encoding.UTF8.GetByteCount(msg) + "\r\n");
                sb.Append("\r\n");
                sb.Append(msg + "\r\n");
                
                Byte[] sendBytes = Encoding.UTF8.GetBytes(sb.ToString());
                netStream.Write(sendBytes, 0, sendBytes.Length);
                netStream.Flush();
            }                        if (netStream.CanRead)
            {
                Thread.Sleep(10); //这个地方加上就能获取到数据，如果去掉大部分时候都不能获取到，只有少数时候能取得
                byte[] bytes = new byte[tcpClient.ReceiveBufferSize];
                netStream.Read(bytes, 0, (int)tcpClient.ReceiveBufferSize);
                string returndata = Encoding.UTF8.GetString(bytes);
                returndata = returndata.Substring(0,returndata.IndexOf('\0'));                Console.WriteLine("returns: " + returndata);
            }
            
            tcpClient.Close();
            netStream.Close();Thread.Sleep(10); //这个地方加上就能获取到数据，如果去掉大部分时候都不能获取到，只有少数时候能取得，求解

Answer 1

StreamReader streamReader = new StreamReader(netStream) 
streamReader.ReadLine()

Answer 2

呵呵，你可真有速度。我也知道是因为响应没回来，我想请教的是如何去掉这个sleep用他原生的方法或者事件来实现同样的效果。

Answer 3

用 ssp2009 的方法搞定，多谢两位

Answer 4

试试 判断 TcpClient.Connected或者用 EndConnect