面试题

Question

Split函数用过吧?
类实现IComparable接口
Set Get用过吧?

Answer 1

实际上是个二维数组嘛，给一个不怎么考虑效率的做法：
1.先splite(',')得到一个string[];
2.把这个string[]填入一个List<string[]>得到一个string[n][5]的数组;
3.接下来嘛，想怎么玩怎么玩呗

Answer 2

struct PersonInfo{name,mail,age,city};splite后就存到数组里面，map<int,PersonInfo*> con.封装好以后提供相应的接口出去就可以了．

Answer 3

A:实现IComparable接口；
B:字符串搜索，质量好坏差别很大；
C:修改文本行呗。

Answer 4

Person.cs
public class Person:IComparable
    {
        private int id, age;
        private string name, email, city;        //申明属性
        public int Id
        {
            get  
            {
                return id;
            }
            set
            {
                id = value;
            }
        }        public int Age
        {
            get
            {
                return age;
            }
            set
            {
                age = value;
            }
        }        public string Name
        {
            get
            {
                return name;
            }
            set
            {
                name = value;
            }
        }        public string Email
        {
            get
            {
                return email;
            }
            set
            {
                email = value;
            }
        }        public string City
        {
            get
            {
                return city;
            }
            set
            {
                city = value;
            }
        }        public override string ToString()
        {
            return "Id = "+ id + " Name = "+name+" Email = "+email+" Age = "+age+" City = "+city ;
        }
    
        #region IComparable 成员        public int  CompareTo(object obj)
            {
                return this.Id.CompareTo(((Person)obj).Id);
            }        #endregion
    }Persons.cs
public class Persons
    {
        private ArrayList al=new ArrayList();
        private Person temp;        public void AddPerson(Person p)
        {
            al.Add(p);
        }        public void Sort()
        {
            al.Sort();
        }        
        public Person this[string info]
        {            get
            {
                foreach (Person p in al)
                {
                    if (p.City == info || p.Name == info)
                        temp= p;
                }
                return temp;
            }
        }        public void Print()
        {
            foreach (Person p in al)
                Console.WriteLine(p.ToString());
        }
    }Main:static void Main(string[] args)
        {
            string stringdb = "1,tony,[email protected],26,tokyo,6,frank,[email protected],18,beijing,3,"+
                "nohara,[email protected],27,fukuoka,2,uehara,[email protected],29,fukujima";            string[] strdata = stringdb.Split(',');            Persons persons = new Persons();
            Person newp=new Person();            for (int i = 0; i < strdata.Length; i++)
            {
                Person p = new Person();                p.Id = Int32.Parse(strdata[i++]);
                p.Name = strdata[i++];
                p.Email = strdata[i++];
                p.Age = Int32.Parse(strdata[i++]);
                p.City = strdata[i];                persons.AddPerson(p);
            }            newp = persons["tony"];            if(newp!=null)
            Console.WriteLine(newp.ToString());
            
            //persons.Sort();
            //persons.Print();

Answer 5

用odbc，将txt文件作为csv数据源，再定义一个类型化数据集，即可实现所要的功能

Answer 6

似乎不难吧 splite(','）就可以分开了。。再慢慢分。。就好了`

Answer 7

nbkyo() ( ) 信
的Person,要改改。#region IComparable 成员        public int  CompareTo(object obj)
            { 
                Person p = obj as Person;
                if (p == null)
                     return false;
                return this.Id.CompareTo(p.Id);
            }        #endregion