如何读取xml文件中某节点16进制的图片数据？

Question

<Data>424dffffff8effffffd60100000000003600</Data>
???
这一段，应该是base64编码
用
byte[] byteimg = System.Convert.FromBase64String( datastring );
获取字节流

Answer 1

按你上面的写会出现下面的错误啊
Base-64 字符数组的无效长度。

Answer 2

已测试可以通过FromBase64String获得byte数组
string str = "424dffffff8effffffd60100000000003600";
byte[] b = System.Convert.FromBase64String( str );
watch：
- b {Length=0x1b} byte[]
[0x0] 0xe3 byte
[0x1] 0x6e byte
[0x2] 0x1d byte
[0x3] 0x7d byte
[0x4] 0xf7 byte
[0x5] 0xdf byte
[0x6] 0x7d byte
[0x7] 0xff byte
[0x8] 0x1e byte
[0x9] 0x7d byte
[0xa] 0xf7 byte
[0xb] 0xdf byte
[0xc] 0x7d byte
[0xd] 0xf7 byte
[0xe] 0x7a byte
[0xf] 0xd3 byte
[0x10] 0x5d byte
[0x11] 0x34 byte
[0x12] 0xd3 byte
[0x13] 0x4d byte
[0x14] 0x34 byte
[0x15] 0xd3 byte
[0x16] 0x4d byte
[0x17] 0x34 byte
[0x18] 0xdf byte
[0x19] 0xad byte
[0x1a] 0x34 byte贴出你的代码看看

Answer 3

如果它不是通过base64编码的，这段代码不行，需要了解具体的数据的编码方式，xml内一般只能放置字符串，二进制数据需要编码。

Answer 4

首先谢谢你的帮忙!这部份的代码如下：
ImgAuthor = xReader.GetAttribute(0);
                        //ImgAuthor=ImgAuthor.Replace("\r","");
                        //ImgAuthor = ImgAuthor.Replace("\n", "");
                        //ImgAuthor = ImgAuthor.Replace("\"", "\\" + "\"");
                        ImgAuthor=DbHelperSQL.InputText(ImgAuthor, 25);
                        Re = xReader.GetAttribute(1);
                        xReader.Read();
                        if (xReader.Name == "Data")
                        {
                            xReader.Read();
                            if (xReader.Value != "Unknown")
                            {
                                Docmodel = new PrjPaper.Model.TabDocuments();
                                Docmodel.Title = Re;
                                Docmodel.DocName = "Img";
                                Docmodel.DocType = "image/bmp";     //"image/pjpeg";
                                //string str = xReader.ReadContentAs(typeof(byte[]), null);
                                string str=xReader.ReadContentAsString();
                                //Docmodel.Contents=xReader.ReadContentAsBase64(typeof(byte[]),0,
                                Docmodel.Contents = System.Convert.FromBase64String(str);
                                //Docmodel.Contents = (byte[])xReader.ReadContentAs(typeof(byte[]), null);
                                //Docmodel.Contents = DbHelperSQL.StringToByte(xReader.ReadContentAs(typeof(string), null));
                                Docmodel.Author = ImgAuthor;
                                Docmodel.Redate = System.Convert.ToDateTime(SpaceDate);
                                DocID = Docbll.Add(Docmodel);                                imgmodel.NewsID = newsmodel.ID;
                                imgmodel.ImgDocID = DocID;
                                imgbll.Add(imgmodel);
                            }
                        }

Answer 5

Data部份太大，我都贴不出来！我有问了写xml文件的程序员，他说是按16进制写的