XML节点值获取

Question

XML  节点读取

Answer 1

没有空间标示，用linq to  xml 吧。
http://blog.csdn.net/duanzi_peng/article/details/24018431

Answer 2

  XmlDocument doc = new XmlDocument();
            doc.Load("1.xml");
          
            XmlNodeList nodes = doc.SelectNodes("/root/buses/bus/segments/segment");
            foreach (XmlNode node in nodes)
            {              
                string start_stat = node.SelectSingleNode("start_stat").InnerText;
                string end_stat = node.SelectSingleNode("end_stat").InnerText;
                string line_name = node.SelectSingleNode("line_name").InnerText;
            }

Answer 3

  XmlDocument doc = new XmlDocument();
            doc.Load("1.xml");
          
            XmlNodeList nodes = doc.SelectNodes("/root/buses/bus/segments/segment");
            foreach (XmlNode node in nodes)
            {              
                string start_stat = node.SelectSingleNode("start_stat").InnerText;
                string end_stat = node.SelectSingleNode("end_stat").InnerText;
                string line_name = node.SelectSingleNode("line_name").InnerText;
            }
正解

Answer 4

供参考
/// <summary>
        /// 根据节点名称 读取PersonalAccountSettings.xml中节点的InnerText值
        /// </summary>
        /// <param name="nodeName">节点名称</param>
        /// <returns>节点值</returns>
        public static string GetPersonalSettings(string nodeName)
        {
            string nodeText = String.Empty;
            try
            {
                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.Load(System.Windows.Forms.Application.StartupPath + "\\Configuration\\PersonalAccountSettings.xml");
                XmlNode xn = xmlDoc.SelectSingleNode("root//" + nodeName + "");
                nodeText = xn.InnerText;
            }
            catch
            { }
            return nodeText;
        }