foreach 、Label

Question

遍历

Answer 1

没遇到过，
我觉得是Label   lab1 = b as Label;这个有问题

Answer 2

MessageBox.Show("datagridview成功！");  你这也算找到控件？？
要DataGridView data = a as DataGridView; 判断 data是否等于null的，不等于null，说明找到了。
另完全看不懂你遍历label中的if语句有什么意义。

Answer 3

不，它只是赋值了，并没有判断lab1是否等于null，所以这段代码没意义。

Answer 4

你这段代码找到Label也会报失败的。

Answer 5

虽然没看懂你的意图，本着得分的心态
foreach (Panel pan in panel2.Controls)
                {
                   
                    if (pan.Name == "pan" + i.ToString())
                    {
                        //遍历datagridview
                        foreach (Control a in pan.Controls)
                        {
                            if (a.Name.Trim() == "data" + i.ToString())
                            {
                               DataGridView data = a as DataGridView;
                               MessageBox.Show("datagridview成功！");
                            }
    else if (b.Name.Trim().ToLower() == "lab" + i.ToString())
                            {
                        //遍历label
                                Label   lab1 = b as Label;
                               MessageBox.Show("Label失败！")
                            }
                        }                    }
 

Answer 6

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foreach (Panel pan in panel2.Controls)
                {
                    
                    if (pan.Name == "pan" + i.ToString())
                    {
                        //遍历datagridview
                        foreach (Control a in pan.Controls)
                        {
                            if (a.Name.Trim() == "data" + i.ToString())
                            {
                               DataGridView data = a as DataGridView;
                               MessageBox.Show("datagridview成功！");
                            }
                else if (a.Name.Trim().ToLower() == "lab" + i.ToString())
                            {
                        //遍历label
                                Label   lab1 = b as Label;
                               MessageBox.Show("Label失败！")
                            }
                        }
 
                    }
  
 

Answer 7

可能是Label的父控件不是pan，而是另外一个可以嵌套Label的控件，这个控件的父控件可能才是pan，
如果是这样，那么foreach  pan的子控件，当然是找不到Label了。

Answer 8

是的，比如pan里面嵌套着一个panel，panel里面有几个label，上面的代码是遍历不到的（这种情况，需要递归遍历）
上面代码做的改掉，主要是忽略标签名大小写的问题

Answer 9

private void YouMethod(Control container)
{
....foreach (Panel pan in panel2.Controls)
                {
                    
                    if (pan.Name == "pan" + i.ToString())
                    {
                        //遍历datagridview
                        foreach (Control a in pan.Controls)
                        {
                            if (a.Name.Trim() == "data" + i.ToString())
                            {
                               DataGridView data = a as DataGridView;
                               MessageBox.Show("datagridview成功！");
                            }
                else if (a.Name.Trim().ToLower() == "lab" + i.ToString())
                            {
                        //遍历label
                                Label   lab1 = b as Label;
                               MessageBox.Show("Label失败！")
                            }//递归
if (a.HasChildren)
    YouMethod(a);
                        }
 
                    }
....
}
  
 增加了递归遍历

Answer 10

第一次调用的时候
YouMethod(panel2);private void YouMethod(Control container)
{
....foreach (Panel pan in container.Controls)
                {
                    
                    if (pan.Name == "pan" + i.ToString())
                    {
                        //遍历datagridview
                        foreach (Control a in pan.Controls)
                        {
                            if (a.Name.Trim() == "data" + i.ToString())
                            {
                               DataGridView data = a as DataGridView;
                               MessageBox.Show("datagridview成功！");
                            }
                else if (a.Name.Trim().ToLower() == "lab" + i.ToString())
                            {
                        //遍历label
                                Label   lab1 = b as Label;
                               MessageBox.Show("Label失败！")
                            }//递归
if (a.HasChildren)
    YouMethod(a);
                        }
 
                    }
....
}
  
 

Answer 11

//遍历datagridview             
    foreach (Control a in pan.Controls)                        {//遍历label                   
     foreach (Control b in pan.Controls)
你这注释不靠谱吖这明明遍历的东西一样所有pan.Controls

Answer 12

foreach (Panel pan in panel2.Controls)
                {
                   
                    if (pan.Name == "pan" + i.ToString())
                    {
                        //遍历datagridview
                        foreach (Control a in pan.Controls)
                        {
                            if (a.Name == "data" + i.ToString())
                            {
                               DataGridView data = a as DataGridView;
                               MessageBox.Show("datagridview成功！");
                            }
                         
                        //遍历label
                     
                            if (a.Name == "lab" + i.ToString())
                            {
                                Label   lab1 = a as Label;
                               MessageBox.Show("Label失败！")
                            }
                        }
                    }把二个if 放在一起。应该就可以了。 可以试一下 。 在用typeof()  判断一下类型

Answer 13

label装在某个容器，而不是直接在窗体中，需要递归遍历下。

Answer 14

 foreach (Control b in pan.Controls)
                        {
                            if (b.Name == "lab" + i.ToString())
                            {
                                Label   lab1 = b as Label;
                               MessageBox.Show("Label失败！")
                            }
                        }注意这行。  MessageBox.Show("Label失败！")
你找到了。 是提示的失败。  

Answer 15

你这样遍历不行哦~~~就拿这段而言
foreach (Control a in pan.Controls)                        
 {               
        if (a.Name == "data" + i.ToString())                  
         {                               
                 DataGridView data = a as DataGridView;                                
                 MessageBox.Show("datagridview成功！");                            
          }                        
 } 
万一a的Name是data+i.ToString()，但它不是DataridView控件呢？？我给你个webform的吧            System.Web.UI.WebControls.TextBox txt;
            System.Web.UI.WebControls.DropDownList ddl;
            foreach (Control MainControl in this.Page.Controls)
            {
                foreach (Control objControl in MainControl.Controls)
                {
                    if (objControl.GetType().ToString() == "System.Web.UI.WebControls.TextBox")
                    {
                        txt = (System.Web.UI.WebControls.TextBox)objControl;
                        if (txt.ClientID != "txtWorker_No" && txt.ClientID != "txtChecker_No" && txt.ClientID != "txtWork_Dt" && txt.ClientID != "txtTemp" && txt.ClientID != "txtChecker_Nm"
                            && txt.ClientID != "txt_SureNm" && txt.ClientID != "txtSign_Nm" && txt.ClientID != "txtWorker_Nm")
                        {
                            txt.Text = "";
                        }
                    }
                    if (objControl.GetType().ToString() == "System.Web.UI.WebControls.DropDownList")
                    {
                        ddl = (System.Web.UI.WebControls.DropDownList)objControl;
                        if (ddl.ClientID != "ddl_Shift" && ddl.ClientID != "ddlPlant_Site_Cd")
                        {
                            ddl.SelectedIndex = -1;
                        }
                    }
                }
            }
            this.txtS_No.Focus();

Answer 16

你还要对比Control的类型吧！！