高手们：如何修改xml中的数据？应者有分。

Question

每次修改后重新生成一个.xml文件，把原来的xml文件覆盖

Answer 1

C#里这样的对象和属性,就像修改INI文件一样,不难

Answer 2

document.LoadXml(Oldxmlfile);
element = document.DocumentElement; 
node = element.FirstChild;
node.Text="新的IP"
document.Save("c:\winnt\myxml.xml")

Answer 3

将
<SysInfo>
         <databaseIP>192.168.2.222</databaseIP>
</SysInfo>
命名为 mDoc.xmlstring m_Document = "mDoc.xml";
XmlTextReader xmlFieldReader = new XmlTextReader(m_Document);
while(xmlReader.Read())
{
     string strCurrentElementName = xmlReader.Value;
     string str = "aaaaaaa";
     XmlTextWriter xmlWriter = new XmlTextWriter(m_Document, Encoding.Default);
     xmlWriter.WriteString(str);
     xmlWriter.Flush();
     xmlWriter.Close();
}xmlReader.Close();

Answer 4

public void WriteXML(XmlWriter w)
{
w.WriteElementString("FlowID",iFid.ToString());
w.WriteElementString("Name",Name);
w.WriteElementString("Description",Description);
w.WriteElementString("Version",Version);
w.WriteElementString("Priority",Priority.ToString());
w.WriteElementString("Status",Status.ToString());
w.WriteElementString("Responsible",Responsible.ToString());
}

Answer 5

public  void LoadXML(ref XmlTextReader xmlRdr)
{
string strFlag;
string strData;
bool bEnd;strFlag = "";
bEnd = false;
while (xmlRdr.Read() && !bEnd)
{
if (xmlRdr.NodeType == XmlNodeType.Element)
strFlag = xmlRdr.Name;//循环退出标志
if (strFlag == "FlowEnd")
bEnd = true;
if (xmlRdr.NodeType == XmlNodeType.Text)
{
strData =  xmlRdr.Value;
switch (strFlag)
{
case "FlowID":
Fid = Convert.ToInt32(strData);
break;
case "Name":
Name = strData;
break;
case "Description":
Description = strData;
break;
case "Version":
Version = strData;
break;
case "Priority":
Priority = Convert.ToInt32(strData);
break;
case "Status":
Status = Convert.ToInt32(strData);
break;
case "Responsible":
Responsible = Convert.ToInt32(strData);
break;
default:
break;
}
}
}

Answer 6

XmlDocument XDoc = new XmlDocument();
XDoc.Load("FileName.xml");
XmlNode cnn = XDoc.SelectSingleNode("descendant::databaseIP");
cnn.InnerText = "Update Text";
XDoc.Save("FileName.xml");