Java ZipInputStream转成C#对应的代码怎么转?

Question

java:    /**
     * 解压byte数组类型的Zip
     * 
     * @param data
     * @return
     * @throws IOException
     */
    private static byte[] unZip(byte[] data) throws IOException {
        byte[] b = null;
        ByteArrayInputStream bis = new ByteArrayInputStream(data);
        ZipInputStream zip = new ZipInputStream(bis);
        while (zip.getNextEntry() != null) {
            byte[] buf = new byte[8096];
            int num = -1;
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            while ((num = zip.read(buf, 0, buf.length)) != -1) {
                baos.write(buf, 0, num);
            }
            b = baos.toByteArray();
            baos.flush();
            baos.close();
        }
        zip.close();
        bis.close();
        return b;
    }请大神帮忙转成C#代码

Answer 1

自己百度“SharpZipLib”

Answer 2

zip压缩解压是统一标准，直接用对应类库就行，没必要纠结与某行具体的代码

Answer 3

GZipStream了解一下
private static byte[] UnZip(byte[] data)
        {
            try
            {
                using (var bis = new MemoryStream(data))
                using (var zip = new GZipStream(bis, CompressionMode.Decompress))
                using (var baos = new MemoryStream())
                {
                    var buf = new byte[8096];
                    var num = -1;
                    while((num = zip.Read(buf,0,buf.Length)) > 0)
                        baos.Write(buf, 0, num);
                    baos.Flush();
                    return baos.ToArray();
                }
            }
            catch (Exception ex)
            {
                throw ex;
            }
        }