C# List<string>序列化XML的问题

Question

定义如下类
[XmlRoot("funderService")]
    public class Request_gl
    {
        public Request_gl()
        {
            ParamList = new List<string>();
        }
        [XmlAttribute]
        public string functionName { get; set; }        [XmlArrayItem("vaule")]
        public List<string> ParamList { get; set; }        public string beanToXml()
        {
            //准备序化列对象
            var format = new XmlSerializer(typeof(Request_gl));
            var stringBuilder = new StringBuilder();            //设置序序化XML格式
            XmlWriterSettings xws = new XmlWriterSettings();
            xws.Indent = true;
            xws.OmitXmlDeclaration = true;
            xws.Encoding = Encoding.UTF8;            XmlWriter xmlWriter = XmlTextWriter.Create(stringBuilder, xws);            //去掉要结点的 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" 属性
            XmlSerializerNamespaces _namespaces = new XmlSerializerNamespaces(
                    new XmlQualifiedName[] {
                        new XmlQualifiedName(string.Empty, string.Empty)  
                 });
            xmlWriter.WriteStartDocument(true);
            format.Serialize(xmlWriter, this, _namespaces);            return stringBuilder.ToString();
        }    }需要序列化成的XML格式如下
<funderService functionName='2023'>          
  <value>1</value>   
  <value>2</value>
  <value>3</value>
</funderService >可实际序列化出来是这样子的<funderService functionName="2023">
  <ParamList>
    <vaule>1</vaule>
    <vaule>2</vaule>
    <vaule>3</vaule>
    <vaule>4</vaule>
  </ParamList>
</funderService>
多了 <ParamList> 节点
请问类型该如何定义才能序列化成想要的

Answer 1

 [XmlArrayItem("vaule")]
//替换为
 [XmlElement("vaule")]