截取指定字符串

string str = "DDD(Y100) ddd";
string num=str.Substring(str.IndexOf("(Y")+2,str.IndexOf(")")-str.IndexOf("(Y")-2);

char[] s = "DDD(Y100) ddd";int startIndex = -1;
int endIndex = -1;
for ( int i = 0; i < s.count; i++)
{
    char c = s[i];

    if (startIndex == -1 && c is a number)  // c >= '0' && c <= '9'
    {
       startIndex = i;
       continue;
    }    if (startIndex >= 0 && c is not a number)
    {
        endIndex = i - 1;
     }     if (startIndex >=0 && endIndex >=0)
      {
        //get substring from startIndex to endIndex
        //output substring
        //reset startIndex and endIndex to -1
      }}

string tempStr = @"DDD(Y1005454) ddd"; string pattern = @"[^\d]*(\d*)";
string outPut = Regex.Replace(tempStr, pattern,"$1");

string str = "DDD(Y100) ddd";
            int begin = str.IndexOf("(Y");
            int end = str.IndexOf(")");
            string result = str.Substring(begin+2, end-5);
            MessageBox.Show(result);
长度可变格式不变
结果://100

var reg = new Regex(@"(?i)(?<=$Y)\d*(?=$)")

不行如果是 Y(Y100)-->9个 3%+0 会得到括号后的数字

Y(Y100)-->9个 3%+0不一定是Y 有可能是其他字符
除了括号里面的数字，其他都是不确定的，但括号里的数字前面一定有一个字母

我的方式你试了吗LZstring str = "DDD(Y100) ddd";
  int begin = str.IndexOf("(");
  int end = str.IndexOf(")");
  string result = str.Substring(begin+2, end-5);
  MessageBox.Show(result);

你这个只能针对"DDD(Y100) ddd"这种格式，Y(Y100)-->9个 3%+0 就不行

string strBegin=""Y(Y100)-->9个 3%+0";";
string str = strBegin.Trim();
            int begin = str.IndexOf("(");
            int end = str.IndexOf(")");
            string result = str.Substring(begin + 2, end - 3);
            MessageBox.Show(result);
//结果:100刚才是考虑到你空格的问题，现在只要是 XXX(.....)XXXXX都能得到

private string f(string sk)
  sk = "ddddjjoo(sdYsd4590ffg)dg";//假设你是这样的
            string tempstr=sk;
            int start=0;
            int end = 0;
            List<string> L = new List<string>();
            for (int n = 0; n < 10;n++ )
            {
                L.Add(n.ToString());
            }
            for (int i = 0; i < sk.Length; i++)
            {
                string c = sk.Substring(i, 1);
                if (L.Contains(c))
                {
                    start = i;
                    break;

                }
                               }
            sk = sk.Substring(start);
            for (int j = 0; j < sk.Length; j++)
            {
                string c = sk.Substring(j, 1);
                if (!L.Contains(c))
                {
                    end = j-1;
                    break;                }
            }
            string result = null;
            if (start != end)
            {
                result = tempstr.Substring(start,end+1);
            }
return result;楼主这个好使，不好使你来砍我，啊哈哈

private string f(string sk)
  sk = "ddddjjoo(sdYsd4590ffg)dg";//假设你是这样的
            string tempstr=sk;
            int start=0;
            int end = 0;
            List<string> L = new List<string>();
            for (int n = 0; n < 10;n++ )
            {
                L.Add(n.ToString());
            }
            for (int i = 0; i < sk.Length; i++)
            {
                string c = sk.Substring(i, 1);
                if (L.Contains(c))
                {
                    start = i;
                    break;

                }
                               }
            sk = sk.Substring(start);
            for (int j = 0; j < sk.Length; j++)
            {
                string c = sk.Substring(j, 1);
                if (!L.Contains(c))
                {
                    end = j-1;
                    break;                }
            }
            string result = null;
            if (start != end)
            {
                result = tempstr.Substring(start,end+1);
            }
return result;
}
少了对括号，汗

private string f(string sk)
{
  sk = "ddddjjoo(sdYsd4590ffg)dg";//假设你是这样的
            string tempstr=sk;
            int start=0;
            int end = 0;
            List<string> L = new List<string>();
            for (int n = 0; n < 10;n++ )
            {
                L.Add(n.ToString());
            }
            for (int i = 0; i < sk.Length; i++)
            {
                string c = sk.Substring(i, 1);
                if (L.Contains(c))
                {
                    start = i;
                    break;

                }
                               }
            sk = sk.Substring(start);
            for (int j = 0; j < sk.Length; j++)
            {
                string c = sk.Substring(j, 1);
                if (!L.Contains(c))
                {
                    end = j-1;
                    break;                }
            }
            string result = null;
            if (start != end)
            {
                result = tempstr.Substring(start,end+1);
            }
return result;
}

     string tempStr = @"Y(Y100)-->9个 3%+";            string pattern = @"[^(]*$[^\d]*(?<value>[\d]*)$[\s\S]*";

            MatchCollection mc = Regex.Matches(tempStr, pattern, RegexOptions.Multiline|RegexOptions.IgnoreCase);
            for (int i = 0; i < mc.Count; i++)
            {
                //string ss = mc[i].Value;//得到-7.0
                //string ss = mc[i].Groups["id"].Value;
                string text = mc[i].Groups["value"].Value;//为100

            }

            List<string> list = new List<string> { "Y(Y100)-->9个 3%+", "DDD(Y100) ddd" };
            Regex reg = new Regex(@"(?i)(?<=$[a-z])\d+(?=$)");
            foreach (string s in list)
                Console.WriteLine(reg.Match(s).Value);
/*
100
100
*/

我也来凑凑热闹（Java写的）：
public String mySubString(String str){
String one=str.substring("DDD(Y".length());//取得：100) ddd
String two=one.substring(one.indexOf(")"));//取得：) ddd
String result=one.substring(0,one.length()-two.length());//以one为基础，从0开始，截取的长度=one-two
return result;
}
测试数据：DDD(Y10000000000000009) ddd 通过。

调试易

截取指定字符串

解决方案 »