如何通过图片的路径及名称将图片显示在GridView中 如何通过图片的路径及名称将图片显示在GridView中 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 GridView里面包含得有你所需要的的这个控件,你可以去看看msdn,那里面就有说到~! 在后台获取到数据源然后在前台绑定你实体类中的字段 <asp:GridView ID="gvStudents" CssClass="gvStudents" runat="server" AutoGenerateColumns="False" onpageindexchanging="gvStudents_PageIndexChanging" onrowcancelingedit="gvStudents_RowCancelingEdit" onrowdeleting="gvStudents_RowDeleting" onrowediting="gvStudents_RowEditing" onrowupdating="gvStudents_RowUpdating" PageSize="3" AllowPaging="true"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:Label ID="lblImageURl" runat="server" CssClass="lblImageURl" Text='<%# Eval("ImgURl") %>'></asp:Label> </EditItemTemplate> </ItemTemplate> </Columns> </asp:GridView> 不好意思,<img src='<%#Eval("ImgUrl")%>' alt="图片名称"/>如果你要显示图片的名字可以用label显示 应该是这样的,把里面的label改成上面的 <asp:GridView ID="GridView1" runat="server"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:Image ID="img1" ImageUrl='<%#Eval("img") %>' runat="server" AlternateText="image lost" /> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView>...this.GridView1.DataSource = ds;this.GridView1.DataBind(); http://liufang-to.blog.163.com/blog/static/617623842008102643410610/http://blog.csdn.net/dongdingbaihe/article/details/4239861 <asp:GridView ID="gvStudents" CssClass="gvStudents" runat="server" AutoGenerateColumns="False" onpageindexchanging="gvStudents_PageIndexChanging" onrowcancelingedit="gvStudents_RowCancelingEdit" onrowdeleting="gvStudents_RowDeleting" onrowediting="gvStudents_RowEditing" onrowupdating="gvStudents_RowUpdating" PageSize="3" AllowPaging="true"> <Columns> <asp:TemplateField> <ItemTemplate> <ItemTemplate> <img src="<%#Eval("图片路径") %>"/> </ItemTemplate> </EditItemTemplate> </ItemTemplate> </Columns> </asp:GridView>试下。 <img src="<%#Eval("图片路径") %>"/>图片路径就是手k的方式,我想的是在后台动态的获取,灵活一些的 与图片的二进制数据库存储和显示 1.将图片以二进制存入数据库2.读取二进制图片在页面显示3.设置Image控件显示从数据库中读出的二进制图片4.GridView中ImageField以URL方式显示图片5.GridView显示读出的二进制图片====================1.将图片以二进制存入数据库//保存图片到数据库protected void Button1_Click(object sender, EventArgs e){ //图片路径 string strPath = "~/photo/03.JPG"; string strPhotoPath = Server.MapPath(strPath); //读取图片 FileStream fs = new System.IO.FileStream(strPhotoPath, FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fs); byte[] photo = br.ReadBytes((int)fs.Length); br.Close(); fs.Close(); //存入 SqlConnection myConn = new SqlConnection("Data Source=127.0.0.1;Initial Catalog=TestDB;User ID=sa;Password=sa"); string strComm = " INSERT INTO personPhoto(personName, personPhotoPath, personPhoto) "; strComm += " VALUES('wangwu', '" + strPath + "', @photoBinary )"; SqlCommand myComm = new SqlCommand(strComm, myConn); myComm.Parameters.Add("@photoBinary", SqlDbType.Binary,photo.Length); myComm.Parameters["@photoBinary"].Value = photo; myConn.Open(); myComm.ExecuteNonQuery(); myConn.Close();}2.读取二进制图片在页面显示//读取图片SqlConnection myConn = new SqlConnection("Data Source=127.0.0.1;Initial Catalog=TestDB;User ID=sa;Password=sa");string strComm = " SELECT personPhoto FROM personPhoto WHERE personName='wangwu' ";SqlCommand myComm = new SqlCommand(strComm, myConn);myConn.Open();SqlDataReader dr = myComm.ExecuteReader();while (dr.Read()){ byte[] photo = (byte[])dr["personPhoto"]; this.Response.BinaryWrite(photo);}dr.Close();myConn.Close();或SqlConnection myConn = new SqlConnection("Data Source=127.0.0.1;Initial Catalog=TestDB;User ID=sa;Password=sa");SqlDataAdapter myda = new SqlDataAdapter(" SELECT personPhoto FROM personPhoto WHERE personName='wangwu' ", myConn);DataSet myds = new DataSet();myConn.Open();myda.Fill(myds);myConn.Close();byte[] photo = (byte[])myds.Tables[0].Rows[0]["personPhoto"];this.Response.BinaryWrite(photo); 3.设置Image控件显示从数据库中读出的二进制图片 ---------------------------------------------SqlConnection myConn = new SqlConnection("Data Source=192.168.0.36;Initial Catalog=TestDB;User ID=sa;Password=sa");SqlDataAdapter myda = new SqlDataAdapter(" SELECT personPhoto FROM personPhoto WHERE personName='wangwu' ", myConn);DataSet myds = new DataSet();myConn.Open();myda.Fill(myds);myConn.Close();byte[] photo = (byte[])myds.Tables[0].Rows[0]["personPhoto"];//图片路径string strPath = "~/photo/wangwu.JPG";string strPhotoPath = Server.MapPath(strPath);//保存图片文件BinaryWriter bw = new BinaryWriter(File.Open(strPhotoPath,FileMode.OpenOrCreate));bw.Write(photo);bw.Close();显示图片this.Image1.ImageUrl = strPath; //4.GridView中ImageField以URL方式显示图片----------------------------<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False"> <Columns> <asp:BoundField DataField="personName" HeaderText="姓名" /> <asp:ImageField DataImageUrlField="personPhotoPath" HeaderText="图片"> </asp:ImageField> </Columns></asp:GridView>后台直接绑定即可 5.GridView显示读出的二进制图片//样板列<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" OnRowDataBound="GridView1_RowDataBound"> <Columns> <asp:BoundField DataField="personName" HeaderText="姓名" /> <asp:ImageField DataImageUrlField="personPhotoPath" HeaderText="图片"> </asp:ImageField> <asp:TemplateField HeaderText="图片"> <ItemTemplate> <asp:Image ID="Image1" runat="server" /> </ItemTemplate> </asp:TemplateField> </Columns></asp:GridView> protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e){ if (e.Row.RowIndex < 0) return; // System.ComponentModel.Container string strPersonName = (string)DataBinder.Eval(e.Row.DataItem, "personName"); Image tmp_Image = (Image)e.Row.Cells[2].FindControl("Image1"); if (!System.Convert.IsDBNull(DataBinder.Eval(e.Row.DataItem, "personPhoto"))) { // byte[] photo = (byte[])DataBinder.Eval(e.Row.DataItem, "personPhoto"); //图片路径 string strPath = "~/photo/" + strPersonName.Trim() + ".JPG"; string strPhotoPath = Server.MapPath(strPath); //保存图片文件 BinaryWriter bw = new BinaryWriter(File.Open(strPhotoPath, FileMode.OpenOrCreate)); bw.Write(photo); bw.Close(); //显示图片 tmp_Image.ImageUrl = strPath; } } C# winform 查找动态生成的控件ComboBox 并赋值 HttpWebRequest URL中 汉字编码问题 c# 在文件复制完成提示 datagridview不能显示数据!急!急!急! 思归,孟子等大侠们请过来帮忙,已经两天了没解决了。 C#登陆界面求助,为什么我就是读不出数据出来!! 如何让DATAGRID与一个文本框相关联? datagrid的单元格能够拆分,合并吗? 很简单,关于Random。 怎样读出mp3文件的详细信息,比如说歌手,曲名,演唱时间等等 替换字符串中的HTML标签 瞧一瞧看一看啦!知道的不知道的都来捧个场吧 c# windows 编程问题
AutoGenerateColumns="False" onpageindexchanging="gvStudents_PageIndexChanging"
onrowcancelingedit="gvStudents_RowCancelingEdit"
onrowdeleting="gvStudents_RowDeleting" onrowediting="gvStudents_RowEditing"
onrowupdating="gvStudents_RowUpdating" PageSize="3" AllowPaging="true">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:Label ID="lblImageURl" runat="server" CssClass="lblImageURl" Text='<%# Eval("ImgURl") %>'></asp:Label>
</EditItemTemplate>
</ItemTemplate>
</Columns>
</asp:GridView>
如果你要显示图片的名字可以用label显示
<asp:GridView ID="GridView1" runat="server">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:Image ID="img1" ImageUrl='<%#Eval("img") %>'
runat="server" AlternateText="image lost" />
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>...
this.GridView1.DataSource = ds;
this.GridView1.DataBind();
AutoGenerateColumns="False" onpageindexchanging="gvStudents_PageIndexChanging"
onrowcancelingedit="gvStudents_RowCancelingEdit"
onrowdeleting="gvStudents_RowDeleting" onrowediting="gvStudents_RowEditing"
onrowupdating="gvStudents_RowUpdating" PageSize="3" AllowPaging="true">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<ItemTemplate>
<img src="<%#Eval("图片路径") %>"/>
</ItemTemplate>
</EditItemTemplate>
</ItemTemplate>
</Columns>
</asp:GridView>
试下。
<img src="<%#Eval("图片路径") %>"/>图片路径就是手k的方式,我想的是在后台动态的获取,灵活一些的