50分请教如何取xml文件中标签里面的数据，如下

Question

请教如何取不同xml文件中标签里面的数据，如下代码所示
要求1是取出number="1"里面的1,2数据
要求2是取出<divisions></divisions>，<beats></beats>,<step></step>,<duration></duration>标签之间的数据--------------------------------------------------------------
<part id="P1">
<measure number="1">
<attributes>
<divisions>2</divisions>
<time>
<beats>4</beats>
<beat-type>4</beat-type>
</time>
<clef>
<sign>G</sign>
<line>2</line>
</clef>
</attributes>
<note>
<pitch>
<step>F</step>
<octave>4</octave>
</pitch>
<duration>1</duration>
<voice>1</voice>
<type>eighth</type>
<stem>up</stem>
</note>
</measure>
<measure number="2">
<note>
<pitch>
<step>D</step>
<octave>4</octave>
</pitch>
<duration>4</duration>
<voice>1</voice>
<type>half</type>
<stem>up</stem>
</note>
<note>
<chord/>
<pitch>
<step>C</step>
<octave>5</octave>
</pitch>
<duration>4</duration>
<voice>1</voice>
<type>half</type>
<stem>up</stem>
</note>
</measure>
<measure number="3">
<note>
<pitch>
<step>D</step>
<octave>4</octave>
</pitch>
<duration>4</duration>
<voice>1</voice>
<type>half</type>
<stem>up</stem>
<notations>
<articulations>
<staccato/>
</articulations>
</notations>
</note>
</measure>
</part>

Answer 1

“要求1是取出number="1"里面的1,2数据”，你想把1，2取出来吗？

Answer 2

是的，要取出来的，因为有可能会有多少nubmer，所以每个nubmer数据都是要取出来的

Answer 3

完整解决：private void button1_Click(object sender, EventArgs e)
        {
            try
            {
                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.Load(@"C:\test.xml");                string path = "part/measure";
                string refPaht = "";//相对路径
                XmlNode tempNode = null;                XmlNodeList nodelist= xmlDoc.SelectNodes(path);//查询所有这种路径的节点                foreach(XmlNode node in nodelist)
                {
                    XmlAttribute attr = node.Attributes["number"];
                    string attrVal=attr.Value;   //属性值                    refPaht = "attributes/divisions";
                    tempNode=node.SelectSingleNode(refPaht);                    if(tempNode!=null)
                    {
                        string div = tempNode.InnerText;   //divisions节点值
                    }
refPaht = "attributes//beats";
                    tempNode=node.SelectSingleNode(refPaht);                    if (tempNode != null)
                    {
                        string beats = tempNode.InnerText;   //beats节点值
                    }                    refPaht = "note//step";
                    tempNode=node.SelectSingleNode(refPaht);                    if (tempNode != null)
                    {
                        string step = tempNode.InnerText;   //step节点值
                    }                    refPaht = "note//duration";
                    tempNode=node.SelectSingleNode(refPaht);                    if (tempNode != null)
                    {
                        string duration = tempNode.InnerText;   //duration节点值
                    }  
                }
}
            catch(Exception ex)
            {
                MessageBox.Show(ex.Message);
            }
        }

Answer 4

http://blog.sina.com.cn/s/blog_6c0affba0100qr9y.htmlC#操作XML文件的方法