急，关于XML序列化的问题

Question

我要得到这样的XML
<?xml version="1.0"?>
<Topic>
  <AnswerList>
    <Solution>
        <Device DeviceId="abc7" DeviceName="ttt7" />
        <Device DeviceId="abc22" DeviceName="ttt33"/>
    </Solution>
    <Solution>
        <Device DeviceId="abc7" DeviceName="ttt7" />
        <Device DeviceId="abc22" DeviceName="ttt33"  />
    </Solution>
  </AnswerList>
</Topic>定义的类为。
class Topic
    {
        public List<Solution> AnswerList { get; set; }
    }class Solution
    {
        public List<Device> DeviceList { get; set; }
    }    [Serializable]
    class Device
    {
        [XmlAttribute(AttributeName="DeviceId")]
        public string DeviceId { get; set; }        [XmlAttribute(AttributeName = "DeviceName")]
        public string DeviceName { get; set; }
可是我得到的结果总是
<?xml version="1.0"?>
<Topic>
  <AnswerList>
    <Solution>
      <DeviceList>
        <Device DeviceId="abc7" DeviceName="ttt7" />
        <Device DeviceId="abc22" DeviceName="ttt33"/>
      </DeviceList>
    </Solution>
    <Solution>
      <DeviceList>
        <Device DeviceId="abc7" DeviceName="ttt7" />
        <Device DeviceId="abc22" DeviceName="ttt33"  />
      </DeviceList>
    </Solution>
  </AnswerList>
</Topic>
这两个节点<Solution>和 <DeviceList>我只想要一个。我改怎么样定义我的类。

Answer 1

Solution是类名自动生成的。我也是想去掉。

Answer 2

蛋疼的要求,好好的序列化不用,非要自己写一套.如果Solution类可以修改,可以这么处理
 public class Solution : IXmlSerializable
    {           
        [XmlIgnore]
        public List<Device> DeviceList { get; set; }        public System.Xml.Schema.XmlSchema GetSchema()
        {
            return null;
        }        public void ReadXml(XmlReader reader)
        {
            //todo...
        }        public void WriteXml(XmlWriter writer)
        {
            foreach (var dev in DeviceList)
            {
                writer.WriteStartElement("Device");
                writer.WriteAttributeString("DeviceId", dev.DeviceId);
                writer.WriteAttributeString("DeviceName", dev.DeviceName);
                writer.WriteEndElement();
            }
        }
    }

Answer 3

试试
[XmlArray("Device"), XmlArrayItem(typeof(Device))]
public List<Device> DeviceList { get; set; }

Answer 4

http://topic.csdn.net/u/20110708/16/90e0a3a8-e237-4e01-afde-c4b1fd5617b6.html?34718

Answer 5

[XmlArray("Device"), XmlArrayItem(typeof(Device))] public List<Device> DeviceList { get; set; }这样没任何变化
[XmlIgnore]，子节点都没有了。感谢huangwenquan123，感谢大家。

Answer 6

[XmlElement("Device")]
public List<Device> DeviceList { get; set; }
这样的
 

Answer 7

是否有检查过Topic类中的AnswerList有几个

Answer 8

class Topic
  {
  public AnswerList  AnswerList { get; set; }
  }class AnswerList :
  {
  public List<Device> DeviceList { get; set; }
  }  [Serializable]
  class Device
  {
  [XmlAttribute(AttributeName="DeviceId")]
  public string DeviceId { get; set; }  [XmlAttribute(AttributeName = "DeviceName")]
  public string DeviceName { get; set; }