C# 怎么把JSON解析到对象

Question

http://json.codeplex.com/http://msdn.microsoft.com/zh-cn/library/system.runtime.serialization.json.datacontractjsonserializer(v=vs.100).aspx

Answer 1

C# 解析JSON的方法：
var json    = {"你的JSON"};
var orders = json.Deserialize<Order>(json); 

Answer 2

var json    = {"response":{"errorCount":0,"orderList":{"order":[{"orderAmount":119,"orderCode":"120914FAYKSR","orderCreateTime":"2012-09-14  
16:46:21","orderDeliveryFee":0,"orderId":75483957,"orderNeedInvoice":2,"orderStatus":"ORDER_TRUNED_TO_DO","productAmount":119,"updateTime":"2012-09-14  
17:05:13"},{"orderAmount":119,"orderCode":"120914TB23GA","orderCreateTime":"2012-09-14  
23:51:25","orderDeliveryFee":0,"orderId":75566567,"orderNeedInvoice":2,"orderStatus":"ORDER_TRUNED_TO_DO","productAmount":119,"updateTime":"2012-09-15  
00:08:14"}]},"totalCount":2}};
var orders = json.Deserialize<Order>(json); 

Answer 3

请参考 C#Json转对象

Answer 4

定义一个 和你json里一样的示例，主要是字段一样

Answer 5

哥们，还是没用啊， 我这个格式跟那个不一样{"response":{"errorCount":0,"orderList":{"order":[{"orderAmount":119,"orderCode":"120914FAYKSR","orderCreateTime":"2012-09-14 16:46:21","orderDeliveryFee":0,"orderId":75483957,"orderNeedInvoice":2,"orderStatus":"ORDER_TRUNED_TO_DO","productAmount":119,"updateTime":"2012-09-14 17:05:13"},{"orderAmount":119,"orderCode":"120914TB23GA","orderCreateTime":"2012-09-14 23:51:25","orderDeliveryFee":0,"orderId":75566567,"orderNeedInvoice":2,"orderStatus":"ORDER_TRUNED_TO_DO","productAmount":119,"updateTime":"2012-09-15 00:08:14"}]},"totalCount":2}}

Answer 6

http://www.cnblogs.com/pen-ink/archive/2011/10/06/2199715.html
这个推荐一下。希望能帮助你。

Answer 7

哥们，方便弄一个demo吗，这种JSON格式的还是有点没搞明白

Answer 8

你这个是嵌套的结构 定义一个response类有errorCount,orderList,totalCount3个属性
其中orderList 是List<order>  定义order类有:":"orderAmount":119,"orderCode":"120914FAYKSR","orderCreateTime":"2012-09-14 16:46:21","orderDeliveryFee":0,"orderId":75483957,"orderNeedInvoice":2,"orderStatus":"ORDER_TRUNED_TO_DO","productAmount":119,"updateTime":"2012-09-14 17:05:13这中的属性就OK了

Answer 9

 protected void Page_Load(object sender, EventArgs e)
    {
        var jdata="[{\"id\":0,\"email\":\"abccd\",\"age\":0},{\"id\":1,\"email\":\"abc1\",\"age\":2}]";
       // string jsonData = context.Request.Form["jdata"];  //取得这个json字符串
        string jsonData = jdata;  //取得这个json字符串
        string datastr = "";         //调用上面这个方法，把json字符串传进去，就得到一个对象集合了
         List<Person> DataReust = JSONToObject<List<Person>>(jsonData);
         for (int i = 0; i < DataReust.Count; i++)
         {
             int id = DataReust[i].id;
             string email = DataReust[i].email;
             int age = DataReust[i].age;
             datastr += "id:" + id + "  email:" + email + " age:" + age+" ";
         }
    }
   
 
     //做一个类id，email，age和json格式一致
     public class Person
     {
        public int id { set; get; }
        public string email { set; get; }
        public int age { set; get; }
     }
 
     //这个一个反序列化的方法，用于返回泛型集合
     public static T JSONToObject<T>(string jsonText)
     {
        JavaScriptSerializer jss = new JavaScriptSerializer();
        return jss.Deserialize<T>(jsonText);
     }