【急】如保将字符串转对象数组

Question

字符串 data="[{id:"1",name:'a'},{id:"2",name:'b'},{id:"3",name:'c'}]"
在C#中如何将字符串转换为数组将其值分个读出。如：d[0].id="1" d[0].name="a"
或者有没有其它更好的办法?
非常感谢！

Answer 1

public class IdName
    {
        public int m_nID        = 0;
        public string m_strName = "";        /// <summary>
        /// 
        /// </summary>
        /// <param name="nID"></param>
        /// <param name="strName"></param>
        public IdName(int nID, string strName)
        {
            this.m_nID = nID;
            this.m_strName = strName;
        }
    }
string str ="[{id:\"1\",name:'a'},{id:\"2\",name:'b'},{id:\"3\",name:'c'}]";            List<IdName> idname = new List<IdName>();
            str = str.Replace("[","").Replace("]","").Replace("{","").Replace("}","").Replace("\"","").Replace("'","");
            string[] strItem = str.Split(new char[] { ',' });
            for (int i = 0; i < strItem.Length; i+=2)
            {
                idname.Add(new IdName(Convert.ToInt32(strItem[i].Substring(3)),strItem[i+1].Substring(5)));
            }
            // 输出效果
            int n1 = idname[0].m_nID;       // 1
            string s1 = idname[0].m_strName;// a            int n2 = idname[1].m_nID;       // 2
            string s2 = idname[1].m_strName;// b
我写的简单，自己添加容错检查

Answer 2

Try : 使用.NET Framwork3.5自带的System.Runtime.Serialization.Json即可很好的完成JSON的解析。
http://www.cnblogs.com/CodingPerfectWorld/archive/2010/08/30/1812628.html
http://space.itpub.net/12639172/viewspace-503464

Answer 3

如是2。0的可以下载个Newtonsoft.Json.dll
        string data="[{id:\"1\",name:'a'},{id:\"2\",name:'b'},{id:\"3\",name:'c'}]";
        JavaScriptArray array = (JavaScriptArray)JavaScriptConvert.DeserializeObject(data);
        for(int i=0;i<array.Count;i++)
        {
            JavaScriptObject obj = (JavaScriptObject)array[i];
            Response.Write(obj["id"] + "==" + obj["name"] + "<br/>");
        }
/*
1==a
2==b
3==c
*/

Answer 4

//3.0以上
        string data = "[{id:\"1\",name:'a'},{id:\"2\",name:'b'},{id:\"3\",name:'c'}]";
        JavaScriptSerializer json = new JavaScriptSerializer();
        List<Data> list = json.Deserialize<List<Data>>(data);
        foreach (Data d in list)
            Response.Write(d.ID + "==" + d.Name + "<br/>");    public class Data
    {
        public string ID;
        public string Name;
    }

Answer 5

System.Runtime.Serialization.Json json解析。当然这个结构简单，分析字符串解析也可以接受。