c# 分析字符串

Question

求助，本人想在如下一大串数据中：
$FYZT,8.91,-4.10,115.06,0.38,0.71,0.41,-0.16,-0.07,0.99,1.01,-205.88,-329.64,366.75*5C\r\n$FYZT,9.00,-4.15,115.06,-0.14,-0.06,0.05,-0.16,-0.07,0.99,1.01,-204.50,-330.01,368.88*93\r\n$FYZT,8.97,-4.08,115.10,-0.00,-0.02,-0.07,-0.16,-0.07,0.99,1.01,-202.38,-330.01,363.88*C4\r\n$FYZT,8.98,-4.10,115.13,0.05,0.26,0.92,-0.16,-0.07,0.99,1.01,-200.88,-330.86,363.13*4D\r\n$FYZT,8.96,-4.13,115.16,0.19,0.32,-0.09,-0.16,-0.07,0.99,1.01,-206.13,-324.61,364.13*75\r\n$FYZT,9.03,-4.11,115.06,0.11,0.22,-0.45,-0.16,-0.07,0.99,1.01,-204.75,-330.13,367.38*68\r\n"
提取出一个数组长度为13的字符串数组，该数组以$FYZT后一个数开始，\r\n前结束，请问我该怎么弄？小弟在此谢过了！

Answer 1

收代码，代码返回的是一个list，list中的每组数据都是符合你条件的一组数据，因为不确定你是要第一个，还是所有符合条件的数据都要，所以我把所有符合条件的数据都取出来了，放在list中，你要做二次处理也很方便。
        public List<string[]> Find13(string raw)
        {
            string[] rawArr = System.Text.RegularExpressions.Regex.Split(raw, @"\r\n");
            List<string[]> list = new List<string[]>();            foreach (string text in rawArr)
            {
                string[] splitArr = System.Text.RegularExpressions.Regex.Split(text, ",");
                if (splitArr.Length.Equals(14) && splitArr[0].Equals("$FYZT"))
                {
                    string[] findArr = new string[13];                    Array.Copy(splitArr, 1, findArr, 0, 13);                    list.Add(findArr);
                }
            }            return list;
        }