求一正则表达式

Question

字符串
  #356823032172848##0#0000#AUT#2#45262726#12641.0418,E,4544.3078,N,002.76,278#180411#033704##
  #356823032172848##0#0000#AUT#2#V#12641.1862,E,1.1861,E,4544.3011,N,000.23,62#190411#015217##规则: 起始字符为 #+15位数字+## 结束字符为## 

Answer 1

GOOD，然后遍历你的字符串就好了

Answer 2

不对, 应该是我描述的不清楚起始字符为 #+15位数字+## + 结束字符为##
如下例
#356823032172848##0#0000#AUT#2#45262726#12641.0418,E,4544.3078,N,002.76,278#180411#033704##注意红色的部分 

Answer 3

(?<=#)\d{15}(?=##)结束是两个##的啊，是不是里面有特殊字符的啊

Answer 4

因为中间有\d{15},ta他只能匹配第一个##

Answer 5

            string str = @"aaaaa
                        #356823032172848##0#0000#AUT#2#45262726#12641.0418,E,4544.3078,N,002.76,278#180411#033704##
                        #356823032172848##0#0000#AUT#2#V#12641.1862,E,1.1861,E,4544.3011,N,000.23,62#190411#015217##
                        bbb";
            Regex reg = new Regex(@"(?<=#)\d{15}##((?!##).)*(?=##)");
            foreach (Match m in reg.Matches(str))
            {
                Response.Write(m.Value + "<br/>");
            }
/*
356823032172848##0#0000#AUT#2#45262726#12641.0418,E,4544.3078,N,002.76,278#180411#033704
356823032172848##0#0000#AUT#2#V#12641.1862,E,1.1861,E,4544.3011,N,000.23,62#190411#015217
*/