xml格式如下:
...
<sensors>
<sensor>1</sensor>
<sensor>2</sensor>
<sensor>3</sensor>
....
</sensors>我想更新其中的一个<sensor>,如把<sensor>3</sensor>更新为:<sensor>4</sensor>请大侠们赐教了!
...
<sensors>
<sensor>1</sensor>
<sensor>2</sensor>
<sensor>3</sensor>
....
</sensors>我想更新其中的一个<sensor>,如把<sensor>3</sensor>更新为:<sensor>4</sensor>请大侠们赐教了!
<sensor>1</sensor>
<sensor>2</sensor>
<sensor>3</sensor>
</sensors>");
doc.Descendants("sensor").OrderBy(x => new Random().Next()).First().Value = "4";
doc.Load("xx.xml");
XmlNode d = doc.SelectSingleNode("//sensor[.='3']");
d.InnerText = "4";
doc.Save("xx.xml");