ftp技术多线程上传图片

Question

我现在想做一个winfrom ,想利用ftp技术进行多线程的上传图片，而且还有进度条显示！请哪个大侠能指点一下，给个例子，谢谢!

Answer 1

只要开一个上传的线程就行了，只要不卡住UI就可以了类似这样的代码
Thread t = new Thread(workThreadFunc);
t.Start();

Answer 2

http://blog.csdn.net/hank212/article/details/6562918

Answer 3

bw = new BackgroundWorker();
                                            bw.WorkerReportsProgress = true;
                                            bw.DoWork += new DoWorkEventHandler(bw_DoWork);
                                            bw.RunWorkerCompleted += new RunWorkerCompletedEventHandler(bw_RunWorkerCompleted);
                                            bw.ProgressChanged += new ProgressChangedEventHandler(bw_ProgressChanged);
                                            bw.RunWorkerAsync(temp);
private void bw_DoWork(object sender, DoWorkEventArgs e)
        {
            ftp 下载
        }

Answer 4

ftp上传图片，你做完了吗？
做完了，放在一个线程里运行，就好了。

Answer 5

比如用webclient
        WebClient wc = new WebClient();
        byte[] data = new byte[10];
        wc.UploadDataCompleted += new UploadDataCompletedEventHandler(wc_UploadDataCompleted);
        wc.UploadDataAsync(new Uri("http://www.sina.com.cn"), data);

Answer 6

这是我上传图片的方法，大家看看怎么弄可以？？
/// <summary>
        /// 上传文件到FTP服务器上【注意：当文件存在时，覆盖原来的文件】
        /// </summary>
        /// <param name="fileName">本地文件路径（例如：d:\ftp_upload1.txt）</param>
        /// <param name="uploadUrl">FTP服务器路径（例如：ftp://192.168.10.176/ftp_upload.txt ）</param>
        /// <param name="userName">用户名</param>
        /// <param name="password">密码</param>
        /// <param name="strResult">执行结果</param>
        /// <returns>0：成功； 1：失败</returns>
        public int UploadFun(string fileName, string uploadUrl, string userName, string password, ref string strResult)
        {
            Stream requestStream = null;
            FileStream fileStream = null;
            FtpWebResponse uploadResponse = null;
            try
            {
                FtpWebRequest uploadRequest = (FtpWebRequest)WebRequest.Create(uploadUrl);
                uploadRequest.Method = WebRequestMethods.Ftp.UploadFile;                uploadRequest.Proxy = null;
                uploadRequest.KeepAlive = true;
                uploadRequest.Method = WebRequestMethods.Ftp.UploadFile;
                uploadRequest.UsePassive = true;
                NetworkCredential nc = new NetworkCredential();
                nc.UserName = userName;
                nc.Password = password;                uploadRequest.Credentials = nc; //修改getCredential();错误2
                requestStream = uploadRequest.GetRequestStream();
                fileStream = File.Open(fileName, FileMode.Open);                byte[] buffer = new byte[1024];
                int bytesRead;
                while (true)
                {
                    bytesRead = fileStream.Read(buffer, 0, buffer.Length);
                    if (bytesRead == 0)
                        break;
                    requestStream.Write(buffer, 0, bytesRead);
                }
                requestStream.Close();                uploadResponse = (FtpWebResponse)uploadRequest.GetResponse();
                if (uploadResponse.StatusCode == FtpStatusCode.ClosingData)
                {
                    strResult = "上传成功,文件:" + fileName;
                    return 0;
                }
                else
                {
                    strResult = "上传文件失败,code=" + uploadResponse.StatusCode.ToString();
                }            }
            catch (UriFormatException ex)
            {
                strResult = ex.Message;
            }
            catch (IOException ex)
            {
                strResult = ex.Message;
            }
            catch (WebException ex)
            {
                strResult = ex.Message;
            }
            finally
            {
                if (uploadResponse != null)
                    uploadResponse.Close();
                if (fileStream != null)
                    fileStream.Close();
                if (requestStream != null)
                    requestStream.Close();
            }            return 1;
        }