[新手提问]c#中对字符串的判断和处理的操作

Question

本帖最后由 oMoWuYan 于 2012-09-02 14:47:32 编辑

Answer 1

这东西别问我们，你自己知道表示什么意思，那就按照你的规则拆分出来就好了，正则可以拆分，普通字符串indexof+substring都可以

Answer 2

string test = @"+90/-5";
            float chengji=0;
            float.TryParse(test,out chengji);
            if (chengji == 0)
            {
                string pattern_com = @"([+-])(\d+(\.\d+)?)";
                Regex.Matches(test, pattern_com).Cast<Match>().ToList().ForEach(a => {
                    if (a.Groups[1].Value.Equals("+"))
                    {
                        chengji += float.Parse(a.Groups[2].Value);
                    }
                    else
                    {
                        chengji -= float.Parse(a.Groups[2].Value);
                    }
                });
            }
            //此时 chengji=85

Answer 3

判断前面没有=号的话
Excel.cell[1,1] = "=" + Excel.cell[1,1]

Answer 4

如果string test  =“+5又很-9”;
应该是报错，实际返回是-4；
这个应该处理呢？

Answer 5

string test = @"+5又很-9";
            float chengji = 0;
            float.TryParse(test, out chengji);
            if (chengji == 0)
            {
                string pattern_match = @"^([+-]\d+/?)+$";
                if (Regex.IsMatch(test, pattern_match))
                {
                    string pattern_com = @"([+-])(\d+(\.\d+)?)";
                    Regex.Matches(test, pattern_com).Cast<Match>().ToList().ForEach(a =>
                    {
                        if (a.Groups[1].Value.Equals("+"))
                        {
                            chengji += float.Parse(a.Groups[2].Value);
                        }
                        else
                        {
                            chengji -= float.Parse(a.Groups[2].Value);
                        }
                    });
                }
                else
                {
                    MessageBox.Show("格式错误");
                }
            }

Answer 6

定义一个函数专门来处理这个： 
private string GetStrExpression(string str){
        
            str = str.Trim();
            string[] ops = str.Split('/');
            int op1Int = int.Parse(ops[0].Trim()),
                op2Int = int.Parse(ops[1].Trim());//获得2个操作数(整型)
            string op2sys = op2Int > 0 ? "+" : "";
            string result = string.Format("{0}{1}{2}={3}", op1Int, op2sys, op2Int, op1Int + op2Int);
            return result;
        }
测试 string dd=  GetStrExpression("+98/-25");
结果 dd="98-25=85"