在winform中DataGridView的问题，感谢各位高手解答！

Question

本帖最后由 CrazySolo1986 于 2010-11-12 11:52:35 编辑

Answer 1

DataGridView.DataSource=你查询到的数据

Answer 2

  List<Bll.Patient> patients = Bll.Patient.GetPatientInHospital(BedCode, "", Context.Current.User.DP_ID, txtPa_Id.Text.Trim());
            
            dgvPatient.Rows.Clear();
            foreach(Bll.Patient patient in patients)
            {
                dgvPatient.Rows.Add();
                int c = dgvPatient.Rows.Count - 1;
                DataGridViewRow row = dgvPatient.Rows[c];
                row.Cells["pId"].Value = patient.Id;
                row.Cells["pName"].Value =patient.BedCode+" "+ patient.Name;
                row.Cells["pPa_Id"].Value = patient.PA_ID;
              //  row.Cells["pBedCode"].Value = patient.BedCode;
                row.Cells["pBirthday"].Value = patient.Birthday;

Answer 3

   if (dt.Rows.Count > 0)
            {
                dgvType.Rows.Clear();
                for (int i = 0; i < dt.Rows.Count; i++)
                {
                    
                    dgvType.Rows.Add();
                    int num = dgvType.Rows.Count - 1;
                    DataGridViewRow row = dgvType.Rows[num];
                    DataRow dr = dt.Rows[i];
                    row.Cells["tId"].Value = dr["ID"].ToString();
                    row.Cells["tcode"].Value = dr["DName"].ToString();
                    row.Cells["tCName"].Value = dr["ChineseName"].ToString();
                    row.Cells["tType"].Value = dr["TypeName"].ToString() == "Task" ? "医护任务" : "协同消息";
                    row.Cells["tAreaID"].Value = dr["DAreaID"].ToString();
                    if (dr["Disabled"].ToString() != "")
                    {
                        row.Cells["tisf"].Value = (bool)dr["Disabled"] ? "启用" : "禁用";
                        row.Cells["tissend"].Value = (bool)dr["IsAllowSended"] ? "是" : "否";
                        row.Cells["trea"].Value = dr["Node"].ToString();
                    }

Answer 4

一种是实体 一种是datatable

Answer 5

直接绑定dataset，觉得这种方法还是可取的

Answer 6

把数据填充到datagridview：dataset.表名.clear();
sqldataadapter.fill(dataset.表名);
datagridview.datasource=dataset.表名;
进行数据更新：你可以直接在datagridview进行修改操作，并结果更新到数据源
sqldataadapter.update(dataset.表名);用到sqldataadapter的fill,update这个两个方法

Answer 7

我还在考虑到底是用LISTVIEW好还是DATAGRIDVIEW好呢纠结~~~