用C#怎么读取XML指定节点下的值？

Question

<Customers>
  <User name="aaa" age="21">
    <Address>
       Shanghai
    </Address>
    <Technology>
       C#
    </Technology>
  </User>
  <User name="bbb" age="22">
    <Address>
       Zhejiang
    </Address>
    <Technology>
       javascript
    </Technology>
  </User>
  <User name="ccc" age="23">
    <Address>
       Zhejiang
    </Address>
    <Technology>
       Delphi
    </Technology>
  </User>
</Customers>--请问，我如果要获取 name="bbb" 的节点下面的 Address节点的值zhejiang，C#应该怎么写呢？

Answer 1

这是参考代码，差不多可以结贴给分了哈！        public SqlConnection GetCon()
        {
            SqlConnection G_Con = null; ;
            try
            {
                string configFile = Path.Combine(Path.GetDirectoryName(Application.ExecutablePath), "参数配置.xml");
                if (File.Exists(configFile))
                {
                    XmlOperator xmlOperator = new XmlOperator(configFile);
                    int size = xmlOperator.GetXmlReader().Length;
                    string[] getDataBaseInfo = new string[size];                    for (int i = 0; i < size; i++)
                    {
                        getDataBaseInfo[i] = xmlOperator.GetXmlReader()[i];
                    }
                    string G_Str_ConnectionString = "Server=" + getDataBaseInfo[0];
                    G_Str_ConnectionString += ";user id=" + getDataBaseInfo[1];
                    G_Str_ConnectionString += ";password=" + getDataBaseInfo[2];
                    G_Str_ConnectionString += ";initial catalog=" + getDataBaseInfo[3] + ";Connect Timeout=20";
                    G_Con = new SqlConnection(G_Str_ConnectionString);
                }
                else
                {
                    MessageBox.Show("不存在配置文件,请添加!");
                    Application.Exit();
                }
            }
            catch (InvalidOperationException ex)
            {
                MessageBox.Show("数据库打开失败,错误原因：" + ex.Message.ToString());
                
            }
            return G_Con;
        }

Answer 2

这是我的XML自己对照一下吧！
<?xml version="1.0" encoding="utf-8"?>
<system>
  <DBServer>localhost</DBServer>
  <UserID>sa</UserID>
  <Pwd>
  </Pwd>
  <DBName>LightCtrl</DBName>
  <ComSet>
    <SeriPort>COM1</SeriPort>
    <BaudRate>19200</BaudRate>
    <DataBits>8</DataBits>
    <Parity>无</Parity>
    <StopBits>1</StopBits>
  </ComSet>
</system>

Answer 3

void Main()
{
   string xml = @"<Customers>
  <User name=""aaa"" age=""21"">
<Address>
   Shanghai
</Address>
<Technology>
   C#
</Technology>
  </User>
  <User name=""bbb"" age=""22"">
<Address>
   Zhejiang
</Address>
<Technology>
   javascript
</Technology>
  </User>
  <User name=""ccc"" age=""23"">
<Address>
   Zhejiang
</Address>
<Technology>
   Delphi
</Technology>
  </User>
</Customers>";
XElement xmlPage = XElement.Parse(xml);
var q = from x in xmlPage.Descendants("User")
where x.Attribute("name").Value == "bbb"
select x.Element("Address").Value;
q.ToList().ForEach(l=>Console.WriteLine(l));
}/*
 Zhejiang
*/

Answer 4

            string xml = @"<Customers>
  <User name=""aaa"" age=""21"">
  <Address>
  Shanghai
  </Address>
  <Technology>
  C#
  </Technology>
  </User>
  <User name=""bbb"" age=""22"">
  <Address>
  Zhejiang
  </Address>
  <Technology>
  javascript
  </Technology>
  </User>
  <User name=""ccc"" age=""23"">
  <Address>
  Zhejiang
  </Address>
  <Technology>
  Delphi
  </Technology>
  </User>
</Customers>";
            XDocument Doc = XDocument.Parse(xml);
            var query = Doc.Descendants("User").Where(x => x.Attribute("name").Value == "bbb").Select(x => x.Element("Address").Value);
            foreach (var v in query)
            {
                Console.WriteLine(v.ToString());

Answer 5

 string resHtml = "<?xml version=\"1.0\" encoding=\"utf-8\" ?> <Customers><User name=\"bbb\" age=\"22\"><Address>Zhejiang</Address><Technology> javascript</Technology></User></Customers>";
                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.LoadXml(resHtml);                XmlNodeList xnl = xmlDoc.SelectNodes("/Customers");
                XmlNodeList linkNOdes = xnl[0].SelectNodes("User");
                foreach (XmlNode linkNode in linkNOdes)
                {
                    foreach (XmlNode xn2 in linkNode.ChildNodes)
                    {
                        if (xn2.Name == "Address")
                        {
                            string name = xn2.InnerText;
                        }
                    }                }

Answer 6

 XmlDocument xmlDoc=new XmlDocument(); xmlDoc.Load("XXX.xml"); // 文件路径
 XmlNodeList nodeList=xmlDoc.SelectSingleNode("Customers").ChildNodes;//获取bookstore节点的所有子节点 foreach(XmlNode xn in nodeList)//遍历所有子节点 { XmlElement xe=(XmlElement)xn;//将子节点类型转换为XmlElement类型 if(xe.GetAttribute("name")== "bbb")
 { 
 MessageBox.Show(xe.SelectSingleNode("Address").InnerText);}
}也可以
xmlDoc.SelectSingleNode("Customers/User[name=bbb]").ChildNodes[0].InnerText;

Answer 7

最简单的方法 string Setadr = System.IO.Directory.GetCurrentDirectory();
        XmlDocument _Documnet = new XmlDocument();//获取程序路径
 _Documnet.Load(Setadr + "/set.xml");//读取此XML
XmlNodeList _NodeList = _Documnet.SelectNodes("Customers/bbb/Address");
            if (_NodeList.Count != 0)
                return _NodeList[0].InnerText;//返回此节点值

Answer 8

  string name = "";
//打开xml文件 
    FileStream myFile = new FileStream(AutoUpdaterFileName, FileMode.Open);
    //xml文件阅读器 
    XmlTextReader xml = new XmlTextReader(myFile);
    while (xml.Read())
    {
        if (xml.Name == "UpdateUser")
        {
            //获取升级文档的最后一次更新日期 
            name = xml.GetAttribute("name");
            break;
        }
    }