关于wp7上httpWebrequest上文件问题

Question

  private void uploadweb_Click(object sender, RoutedEventArgs e)
              {
                  // string url = "ftp://172.16.149.28:80";
                   string url = "http://webservice.webxml.com.cn/WebServices/MobileCodeWS.asmx";
                  // string url = "http://www.oschina.net/wp7";
                  using (IsolatedStorageFile isf = IsolatedStorageFile.GetUserStoreForApplication())
                  {
                      using (IsolatedStorageFileStream sendingZipStream = new IsolatedStorageFileStream("myFile.txt", FileMode.Open, isf))
                      {
                          try
                          {
                              // 要上传的文件 
                              bSendingFile = new byte[sendingZipStream.Length];
                              sendingZipStream.Read(bSendingFile, 0, bSendingFile.Length);
                              HttpWebRequest httpReq = (HttpWebRequest)WebRequest.Create(new Uri(url, UriKind.Absolute));
                              httpReq.Method = "POST";
                              //httpReq.ContentType = "multipart/form-data;";
                              httpReq.ContentType = "Text/html";
                              // httpReq.BeginGetResponse(WebResponseCallback, httpReq);
                              IAsyncResult asyncResult = httpReq.BeginGetRequestStream(new AsyncCallback(RequestStreamCallback), httpReq);
                          }                          catch (Exception ex)
                          {
                              String strError = ex.ToString();
                              MessageBox.Show("获取失败");
                          }
                      }
                  }
              } 
        /// <summary>
 
        /// 返回用于将数据写入Stream，写入数据，并发送
 
        /// </summary>
 
        /// <param name="result"></param>
 
        private void RequestStreamCallback(IAsyncResult result)
        {
            HttpWebRequest request = result.AsyncState as HttpWebRequest;
            // 返回用于将数据写入某 URI 资源的 Stream 
            Stream requestStream = request.EndGetRequestStream(result);
            requestStream.Write(bSendingFile, 0, bSendingFile.Length);
            requestStream.Flush();
            requestStream.Close();
            request.BeginGetResponse(new AsyncCallback(ResponseCallback), request);
        }
 
        /// <summary>
 
        /// 获取最终的返回结果
 
        /// </summary>
 
        /// <param name="result"></param>        private void ResponseCallback(IAsyncResult result)
        {
            try
            {
                HttpWebRequest request = (HttpWebRequest)(result.AsyncState);
                StreamReader response = new StreamReader(request.EndGetResponse(result).GetResponseStream());
                string data = response.ReadToEnd(); //将Stream转为String
                data = data.Substring(0, 1024);//只获取前1024个字符。               
                Dispatcher.BeginInvoke(() =>         //传给主线程结果
                 {
                     MessageBox.Show(data);
                 });
            }
            catch
            {
                Dispatcher.BeginInvoke(() =>         //传给主线程结果
                 {
                     MessageBox.Show("获取失败");
                 });
            }
        }程序代码如上，我想知道为什么 使用string url = "http://www.oschina.net/wp7";时可以返回信息
但换一个网址就不行？就一直提示“获取失败”。
例如我想 string url = "http://webservice.webxml.com.cn/WebServices/MobileCodeWS.asmx";
应该要怎么设置？求高手解答下，我刚学习这方面内容

Answer 1

这个方法可以吗？ 我测试只能获取到你请求页面的源码啊？
并不能把你本地的文件上传啊