try
{ string strappdir = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase);
string infofile = Path.Combine(strappdir, "data.xml");
XmlDocument doc = new XmlDocument();
doc.Load(infofile);
Cursor.Current = Cursors.WaitCursor;
XmlNodeReader reader = new XmlNodeReader(doc);
DataSet ds = new DataSet();
ds.ReadXml(reader);
reader.Close();
DataTable dt = ds.Tables[0];
this.dataGrid1.DataSource = dt.DefaultView;
Cursor.Current = Cursors.Default;
}
catch(XmlException e)
{
MessageBox.Show(e.Message);
}
报找不文件,请问代码要如何写还能把xml获取出来呢,请高手帮帮忙啊
{ string strappdir = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase);
string infofile = Path.Combine(strappdir, "data.xml");
XmlDocument doc = new XmlDocument();
doc.Load(infofile);
Cursor.Current = Cursors.WaitCursor;
XmlNodeReader reader = new XmlNodeReader(doc);
DataSet ds = new DataSet();
ds.ReadXml(reader);
reader.Close();
DataTable dt = ds.Tables[0];
this.dataGrid1.DataSource = dt.DefaultView;
Cursor.Current = Cursors.Default;
}
catch(XmlException e)
{
MessageBox.Show(e.Message);
}
报找不文件,请问代码要如何写还能把xml获取出来呢,请高手帮帮忙啊
string infofile = Path.Combine(strappdir, "\\data.xml");