list_old={1,2,3,4};
list_new={2,3,5,7,8};要的结果:
list_new中的5,7,8对于list_old是新增的,
list_old中的1,4在list_new中式不存在的。求比较高效的方法,语言或代码描述。目前思路,
foreach nid in list_new
{
if(nid not in list_old) nid add to 新增的;
}
foreach oid in list_old
{
if(oid not in list_new) oid add to 不存在的;
}
list_new={2,3,5,7,8};要的结果:
list_new中的5,7,8对于list_old是新增的,
list_old中的1,4在list_new中式不存在的。求比较高效的方法,语言或代码描述。目前思路,
foreach nid in list_new
{
if(nid not in list_old) nid add to 新增的;
}
foreach oid in list_old
{
if(oid not in list_new) oid add to 不存在的;
}
int[] list_old={1,2,3,4};
int[] list_new = { 2, 3, 5, 7, 8 };
int[] except = list_new.Except(list_old).ToArray();
int[] list_old = { 1, 2, 3, 4 };
int[] list_new = { 2, 3, 5, 7, 8 };
int[] append = list_new.Except(list_old).ToArray();//new
int[] removed = list_old.Except(list_new).ToArray();//removed
Console.WriteLine("新增:");
append.ToList().ForEach(n => Console.Write(n+"\t"));
Console.WriteLine();
Console.WriteLine("删除:");
removed.ToList().ForEach(n => Console.Write(n+"\t"));
结果:新增:
5 7 8
删除:
1 4
IList<int> list_old = new List<int>();
IList<int> list_new = new List<int>(); list_old.Add(1);
list_old.Add(2);
list_old.Add(3);
list_old.Add(4); list_new.Add(2);
list_new.Add(3);
list_new.Add(5);
list_new.Add(7);
list_new.Add(8); IEnumerable<int> list_intersect=list_old.Intersect(list_new);
IEnumerable<int> list_old_except_new = list_old.Except(list_new);
IEnumerable<int> list_new_except_old = list_new.Except(list_old); string Result = "";
Result += "list_old:1,2,3,4<br />";
Result += "list_new:2,3,5,7,8<br />";
Result += "交集为:<br />";
foreach (int n in list_intersect)
{
Result += n.ToString() + ",";
}
Result += "<br />list_old_except_new:<br />";
foreach (int n in list_old_except_new)
{
Result += n.ToString() + ",";
}
Result += "<br />list_new_except_old:<br />";
foreach (int n in list_new_except_old)
{
Result += n.ToString() + ",";
}
Response.Write(Result);result:
list_old:1,2,3,4
list_new:2,3,5,7,8
交集为:
2,3,
list_old_except_new:
1,4,
list_new_except_old:
5,7,8, That's OK!