ShowDialog用法问题？

Question

我有两个窗口:Form1和Phone,Phone上有两个Button:btnOK和btnCancel,我现在想实现这样的效果，点btnOK,显示Form1,点btnCancel两个窗口都不显示，我的代码是：
Form1:public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();            Phone frm = new Phone();            while (true)
            {
                frm.ShowDialog();
                if (frm.DialogResult == DialogResult.OK)
                {
                    if (frm.PhoneNumber == "0755")
                    {
                        break;
                    }
                    else
                    {
                        MessageBox.Show("输入错误");
                    }
                }                else if (frm.DialogResult == DialogResult.Cancel)
                {
                    break;
                }
            }            frm.Close();
        }
    }Phone:public partial class Phone : Form
    {
        public Phone()
        {
            InitializeComponent();            btnOK.DialogResult = DialogResult.OK;
            btnCancel.DialogResult = DialogResult.Cancel;
        }        public string PhoneNumber
        {
            get { return txtPhoneNumber.Text; }
            set { txtPhoneNumber.Text = value; }
        }
    }

Answer 1

public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();            Phone frm = new Phone();            while (true)
            {
                frm.ShowDialog();
                if (frm.DialogResult == DialogResult.OK)
                {
                    if (frm.PhoneNumber == "0755")
                    {
                        break;
                    }
                    else
                    {
                        MessageBox.Show("输入错误");
                    }
                }                else if (frm.DialogResult == DialogResult.Cancel)
                {
                    break;
                }
            }            this.Close();
        }
    }

Answer 2

可以实现，但是，点btnCancel后，两个窗口都不显示，但是，会报错“无法访问已释放的对象。对象名：Form1”

Answer 3

修改代码！这部分代码转移到Load事件中！        public Form1()
        {
            InitializeComponent();
            //frm.Close();        }        private void Form1_Load(object sender, EventArgs e)
        {
            Phone frm = new Phone();            while (true)
            {
                frm.ShowDialog();
                if (frm.DialogResult == DialogResult.OK)
                {
                    if (frm.PhoneNumber == "0755")
                    {
                        break;
                    }
                    else
                    {
                        MessageBox.Show("输入错误");
                    }
                }                else if (frm.DialogResult == DialogResult.Cancel)
                {
                    break;                }
            }
            this.Close();
        }