C#中怎么获得xml节点的值？

Question

<?xml version="1.0" encoding="utf-8" ?> 
<LocalPara xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <DataBaseType>1</DataBaseType> 
  <ServerIp>127.0.0.1</ServerIp> 
  <Database>mw_db</Database> 
  <Uid>sa</Uid> 
  <Pwd>sasa</Pwd> 
  <SDE_Port>5151</SDE_Port> 
  <SDE_VER>90</SDE_VER> 
  <ThrowBFrame>0</ThrowBFrame> 
 </LocalPara>
如我有这样一个xml文件，我想获得<SDE_VER>节点的值，怎么获取？

Answer 1

XmlDocument doc = new XmlDocument();
                doc.Load(filename);
                XmlNodeList list = doc.ChildNodes;
                foreach (XmlNode xn in list)
                {
                    if (xn.Name == "SDE_VER")
                    {
                        return ne.InnerText
                    }
                }

Answer 2

 XmlDocument xmlDocument = new XmlDocument();
            xmlDocument.Load(filename);
            xmlDocument.SelectSingleNode("/LocalPara/SDE_VER").InnerText;

Answer 3

谢谢4楼的，简单快捷！~~
2楼那个获不到LocalPara的子节点，不过还是谢谢了！~