怎样读取16进制中的乱码

Question

图片是这样的，怎样用C#读取蓝色这部分成为字符串，这个文件以AA为节点，分为若干个字符串，
根据论坛上兄弟们提供的方法：
Stream sr = new FileStream(@"F:/999999999999999120100411.bin", FileMode.Open);
                    BinaryReader br = new BinaryReader(sr);
                    while (true)
                    {
                        try
                        {                            byte b = br.ReadByte();
                            if (b == 0xAA)
                            {
                                short len = br.ReadInt16();
                                byte[] buffer = br.ReadBytes(len-3);
                                string s = Encoding.Default.GetString(buffer,0,35);
                               MessageBox.Show(s);
                            }
                            else
                            {
                                MessageBox.Show("数据格式错误！");
                                break;
                            }
                        }
                        catch
                        {
                            break;
                        }
                    }
                    br.Close();
                    sr.Close();得到的s是"080010000000120100411151343\0\0\0\0\0\0\0"，
message.show(s)就等于080010000000120100411151343 了，怎样把3后面的那部分读出来，请赐教！ 

Answer 1

  byte[] buffer = br.ReadBytes(len-3);
  string s = Encoding.Default.GetString(buffer,0,35);怎么 35 写死啦！