c#如何获取openFileDialog的“确定”事件

Question

请问如何获取openFileDialog的“确定”事件啊？情况是这样的，我用一个“打开”按钮，触发openFileDialog控件，当我点击“确定”时，判断是否将文件复制到另一个文件夹里！就是后面的获取“确定”不会做啊！请问如何判断我是否点击了“确定”

Answer 1

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Runtime.InteropServices;
using System.Diagnostics;namespace WindowsApplication1
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }        private void Form1_Load(object sender, EventArgs e)
        {            Process[] proc = Process.GetProcesses();
            foreach (Process p in proc)
            {
                Console.WriteLine(p.MainWindowHandle.ToString());
            }            OpenFileDialog of = new OpenFileDialog();
          DialogResult dr=  of.ShowDialog();
          if (dr == DialogResult.OK)
          {
              MessageBox.Show("你点击的是确定按钮");
          }
          else
          {
              MessageBox.Show("你点击的不是确定按钮");
          }
        }
    }
}判断ShowDialog方法的回传值.

Answer 2

OpenFileDialog openFileDialog1 = new OpenFileDialog();
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
//获取文件名做处理
openFileDialog1.FileName
}

Answer 3

if  (openFileDialog1.ShowDialog()  ==  DialogResult.OK) 
  { 
          string  fileName  =  openFileDialog1.FileName; 
          FileInfo  info  =  new  FileInfo(fileName); 
      
  }