Graphics.ScaleTransform(Single, Single)

Question

为什么使用Graphics.ScaleTransform(0.5f,0.5f)可以,而使用:float x = 图象.Image.Size.Width;
Graphics.ScaleTransform(x,x);
却不行?这样也不行:
float x = (float)图象.Image.Size.Width;
Graphics.ScaleTransform(x,x);这样更不行,运行中都停下来报错:
float x = (float)(600/图象.Image.Size.Width);
Graphics.ScaleTransform(x,x);分快没了,高手简单说说就行!

Answer 1

Graphics.ScaleTransform(0.5f,0.5f)
表示缩放后的宽是原来的0.5倍,长也是原来的0.5倍float x = (float)图象.Image.Size.Width;
Graphics.ScaleTransform(x,x);
缩放后的长,宽是原来的x倍,这样新得到的图片长宽太大,假设原来x是100,现在就是10000了,在内存中放不下这么大的图片自然就会报错了

Answer 2

还不行,代码如下:        private void 显示模板_Load(object sender, EventArgs e)
        {
            if (图象.Image.Size.Height > 600 || 图象.Image.Size.Width > 600)
            {
                float x = (float)(600 / 图象.Image.Size.Width);
                float y = (float)(600 / 图象.Image.Size.Height);
                Image magnifyimage = new Bitmap(图象.Image.Size.Width, 图象.Image.Size.Height);
                using (Graphics g = Graphics.FromImage(magnifyimage))
                {
                    if (图象.Image.Size.Width > 图象.Image.Size.Height)
                    {
                        g.ScaleTransform(x, x);
                        //g.ScaleTransform(0.1f, 0.1f);
                    }
                    else
                    {
                        g.ScaleTransform(y, y);
                        //g.ScaleTransform(0.1f, 0.1f);
                    }
                    g.DrawImage(图象.Image, 0, 0);
                }
                图象.Image = magnifyimage;   
   
            }老报错,不知道什么原因.