已经可见的窗体不能显示为模式对话框.在调用 showDialog 之前应将窗体的 Visible

Question

/// <summary>
        /// grid行点击事件
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void dgvStockRecord_CellClick(object sender, DataGridViewCellEventArgs e)
        {
            try
            {
                // 点击详细
                if (e.ColumnIndex == 4)
                {
                    if (this.dgvStockRecord.Rows[e.RowIndex].Cells["ProductId"].Value != null)
                    {
                        // 给参数赋值
                        this.ProductID = this.dgvStockRecord.Rows[e.RowIndex].Cells["ProductId"].Value.ToString();
                    }                    // 弹出库存记录详细信息
                    StockRecordDetail frmStockRecordDetail = new StockRecordDetail();
                    //frmStockRecordDetail.Visible = false;
                    frmStockRecord.ShowDialog();
                }
            }
            catch (Exception ex)
            {
                MsgBox.Err(ex.Message);
            }
        }这段代码在运行时报“已经可见的窗体不能显示为模式对话框.在调用 showDialog 之前应将窗体的 Visible”！请问大家如何解决

Answer 1

if(frmStockRecord.Visible){
frmStockRecord.Visible=false;
}
frmStockRecord.ShowDialog();

Answer 2

看LZ的调用方法应该没有问题。问题是不是出在StockRecordDetail的构造函数上面。