关于C#读取 XML文件问题

Question

     public bool CreateNode(XmlNode Node)
        {
            UserInFo User = new UserInFo();
            foreach (XmlNode Read in Node)
            {
                if (Read.Name == "User_ID")
                {
                    User.U_ID = Read.InnerText;
                }
                if (Read.Name == "User_Name")
                {
                    User.U_Name = Read.InnerText;
                }
                if (Read.Name == "Password")
                {
                    User.U_Password = Read.InnerText;
                }
                if (Read.Name == "TokenPIN")
                {
                    User.U_TokenPIN = Read.InnerText;
                }
                if (Read.Name == "FullName")
                {
                    User.U_FullName = Read.InnerText;
                }
            }
            if (User.U_Name != null && User.U_Password != null && User.U_TokenPIN != null)
            {
                User_Array.Add(User);
            }            return true;
        }按我现在的取法 假设我区 ID 为 001 的对象值
  <User>
    <User_ID>001</User_ID>
    <User_Name>aaa </User_Name>
    <Password>n</Password>
    <TokenPIN>5566</TokenPIN>
    <FullName>ailsa</FullName>
 </User>
 那么 要循环 5次 才能取完
这样查找效率很低，能不能一下就能取出XML文件中 某个对象的所有值 。
xml文件：
<?xml version="1.0" encoding="utf-8"?>
<UserFileNurse>
  <User>
    <User_ID>001</User_ID>
    <User_Name>aaa </User_Name>
    <Password>n</Password>
    <TokenPIN>5566</TokenPIN>
    <FullName>ailsa</FullName>
 </User>
  <User>
    <User_ID>002</User_ID>
    <User_Name>bbb</User_Name>
    <Password>a</Password>
    <TokenPIN>5986</TokenPIN>
    <FullName>amanda</FullName>
 </User>
  <User>
    <User_ID>003</User_ID>
    <User_Name>ccc</User_Name>
    <Password>b</Password>
    <TokenPIN>2366</TokenPIN>
    <FullName>crystal</FullName>
 </User>
</UserFileNurse>

Answer 1

用xpath啊
XmlDocument doc = new XmlDocument();
doc.loadxml();
XmlNode n ;
n = doc.DocumentElement.SelectSingleNode("//User[UserID='User_ID']");
User.U_ID = n.ChildNodes[0].InnerText; 

Answer 2

反序列化呀
class User
{
    User_ID;
    User_Name;
    Password;
    TokenPIN;
    FullName;
}
......

Answer 3

FilePath = "XML/PatientInfo.xml";
            PatientManager My_Node = new PatientManager();
            XmlDocument Xmldoc = new XmlDocument();
            Xmldoc.Load(FilePath);
            XmlNodeList Nodelist = Xmldoc.DocumentElement.ChildNodes;
            //XmlNodeList Nodelist = Xmldoc.SelectSingleNode("Group").ChildNodes;
            
            foreach (XmlNode XNode in Nodelist)
            {
                My_Node.CreateNode(XNode); //这里调用下面的方法 点一次创建个对象并赋值给对象里的变量。 然后到下面的方法里又调用了 好多次 感觉好麻烦呀 就是想 一下取到所有值。 
 public bool CreateNode(XmlNode Node) 
        { 
            UserInFo User = new UserInFo(); 
            foreach (XmlNode Read in Node) 
            { 
                if (Read.Name == "User_ID") 
                { 
                    User.U_ID = Read.InnerText; 
                } 
                if (Read.Name == "User_Name") 
                { 
                    User.U_Name = Read.InnerText; 
                } 
                if (Read.Name == "Password") 
                { 
                    User.U_Password = Read.InnerText; 
                } 
                if (Read.Name == "TokenPIN") 
                { 
                    User.U_TokenPIN = Read.InnerText; 
                } 
                if (Read.Name == "FullName") 
                { 
                    User.U_FullName = Read.InnerText; 
                } 
            } 
            if (User.U_Name != null && User.U_Password != null && User.U_TokenPIN != null) 
            { 
                User_Array.Add(User); 
            }             return true; 
        }             }

Answer 4

public class UserFileNurse
    {
        [XmlElement("User")]
        public User[] Users;
    }
    public class User
    {
        public string User_ID;
        public string User_Name;
        public string Password;
        public string TokenPIN;
        public string FullName;
    }XmlSerializer xs = new XmlSerializer(typeof(UserFileNurse));
UserFileNurse uf = xs.Deserialize(File.OpenRead("test.xml")) as UserFileNurse;

Answer 5

public bool CreateNode(XmlNode Node) 
        { 
            
            foreach (XmlNode Read in Node) 
你这个写法有问题,要么为CreateNode(xmlnodlist nodes),然后才能用Foreach

Answer 6

我这写法没问题呀 在CreateNode(xmlnodlist nodes)被调的时候还有一次foreach 循环呢

Answer 7

FilePath = "XML/PatientInfo.xml";
            PatientManager My_Node = new PatientManager();
            XmlDocument Xmldoc = new XmlDocument();
            Xmldoc.Load(FilePath);
            XmlNodeList Nodelist = Xmldoc.DocumentElement.ChildNodes;
            //XmlNodeList Nodelist = Xmldoc.SelectSingleNode("Group").ChildNodes;
            
            foreach (XmlNode XNode in Nodelist)
            {
                My_Node.CreateNode(XNode);
            }
调用了class PatientManager 的public bool CreateNode(XmlNode Node) 方法public bool CreateNode(XmlNode Node)
        {
            PatientInFo Patient = new PatientInFo();            foreach (XmlNode Read in Node)
            {
                if (Read.Name == "ID")
                {
                    Patient.ID = Read.InnerText;
                }
                if (Read.Name == "Last_Name")
                {
                    Patient.Last_Name = Read.InnerText;
                }
                      .
                      .
                      .
                      .
            }
}
我是这样调用去查找 并得到值的 哎~~~就想一下取出所有值

Answer 8

yuloukong  你刚才 说 楼上正解  我不知道你说的是谁的 是 反序列化的还是哪位的 我都晕了不知道哪个了。

Answer 9

FilePath = "XML/PatientInfo.xml"; 
            PatientManager My_Node = new PatientManager(); 
            XmlDocument Xmldoc = new XmlDocument(); 
            Xmldoc.Load(FilePath); 
            XmlNodeList Nodelist = Xmldoc.DocumentElement.ChildNodes; 
            //XmlNodeList Nodelist = Xmldoc.SelectNodes("//User");
            
            foreach (XmlNode XNode in Nodelist) 
            { 
                My_Node.CreateNode(XNode);  
            }public bool CreateNode(XmlNode Node) 
        { 
            UserInFo User = new UserInFo(); 
            
            User.U_ID = XNode.ChildNodes[0].InnerText;  
       
            User.U_Name = XNode.ChildNodes[1].InnerText; 
   
            User.U_Password = XNode.ChildNodes[2].InnerText;            
    
            User.U_TokenPIN = XNode.ChildNodes[3].InnerText;                
   
            User.U_FullName = XNode.ChildNodes[4].InnerText; 
              
            if (User.U_Name != null && User.U_Password != null && User.U_TokenPIN != null) 
            { 
                User_Array.Add(User); 
            }             return true; 
        } 
 

Answer 10

FilePath = "XML/PatientInfo.xml"; 
            PatientManager My_Node = new PatientManager(); 
            XmlDocument Xmldoc = new XmlDocument(); 
            Xmldoc.Load(FilePath); 
 
            XmlNodeList Nodelist = Xmldoc.DocumentElement.SelectNodes("//User");
            
            foreach (XmlNode XNode in Nodelist) 
            { 
                My_Node.CreateNode(XNode);  
            }
//为什么不用xpath呢
public bool CreateNode(XmlNode Node) 
        { 
            UserInFo User = new UserInFo(); 
            
            User.U_ID = XNode.ChildNodes[0].InnerText;  
       
            User.U_Name = XNode.ChildNodes[1].InnerText; 
   
            User.U_Password = XNode.ChildNodes[2].InnerText;            
    
            User.U_TokenPIN = XNode.ChildNodes[3].InnerText;                
   
            User.U_FullName = XNode.ChildNodes[4].InnerText; 
              
            if (User.U_Name != null && User.U_Password != null && User.U_TokenPIN != null) 
            { 
                User_Array.Add(User); 
            }             return true; 
        } 
 

Answer 11

都这么具体了，还让给例子
UserFileNurse uf = xs.Deserialize(File.OpenRead("test.xml")) as UserFileNurse; 
string s=uf.Users[0].User_ID;
string s2=uf.Users[1].Name;
......
会了吧？

Answer 12

会了  我用 恐惧之狼 的方法实现了 谢谢你们了 感谢 soaringbird  yuloukong