openFileDialog的问题

Question

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;namespace WindowsApplication4
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }        private void button1_Click(object sender, EventArgs e)
        {            openFileDialog1.Title = "Open Image File";
            openFileDialog1.Filter = "Bitmap Files|*.bmp";
            openFileDialog1.FileName = "";
            openFileDialog1.ShowDialog();
            textBox1.Text = openFileDialog1.FileName;
        }
    }
}
这是我的代码，但运行后openFileDialog不能用！请高手帮忙解答一下！

Answer 1

这样
//关闭之前看文件是否保存
        private void MyNotePad_FormClosing(object sender, FormClosingEventArgs e)
        {
            if (this.textBox1.Text != "")
            {
                if (!File.Exists(this.Text))
                {
                    DialogResult d = MessageBox.Show("文件 " + this.Text + @" 的文字已经改变。
想保存文件吗？", "MyNotePad", MessageBoxButtons.YesNoCancel, MessageBoxIcon.Information, MessageBoxDefaultButton.Button1, MessageBoxOptions.DefaultDesktopOnly);
                    switch (d)
                    {
                        case DialogResult.Yes:
                            using (SaveFileDialog saveDig = new SaveFileDialog())
                            {
                                saveDig.Filter = @"文本文档(*.txt)|*.txt";
                                saveDig.FileName = "*.txt";
                                if (saveDig.ShowDialog() == DialogResult.OK)
                                {
                                    StreamWriter sw = new StreamWriter(saveDig.FileName, false, System.Text.Encoding.Default);
                                    sw.Write(this.textBox1.Text);
                                    sw.Close();
                                    this.Text = saveDig.FileName;
                                }
                            }
                            break;
                        case DialogResult.No:
                            break;
                        case DialogResult.Cancel:
                            break;                        default: System.Diagnostics.Debug.Assert(false);
                            break;
                    }
                }
            }
        }本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/LCL_data/archive/2009/06/11/4260509.aspx

Answer 2

你想要怎么用呢？
想得到路径？？？？那么openFileDialog1你少了一个事件，点击确定事件~!

Answer 3

using (SaveFileDialog saveDig = new SaveFileDialog())
                            {
                                saveDig.Filter = @"文本文档(*.txt)|*.txt";
                                saveDig.FileName = "*.txt";
                                if (saveDig.ShowDialog() == DialogResult.OK)
                                {
                                    StreamWriter sw = new StreamWriter(saveDig.FileName, false, System.Text.Encoding.Default);
                                    sw.Write(this.textBox1.Text);
                                    sw.Close();
                                    this.Text = saveDig.FileName;
                                }
                            }
你不试试？  if (saveDig.ShowDialog() == DialogResult.OK)

Answer 4

在你的 button1的事件改一下
private void button1_Click(object sender, EventArgs e) 
        {             openFileDialog1.Title = "Open Image File"; 
            openFileDialog1.Filter = "Bitmap Files|*.bmp"; 
            openFileDialog1.FileName = ""; 
            openFileDialog1.ShowDialog(); 
            textBox1.Text = openFileDialog1.FileName; 
             if (openFileDialog1.ShowDialog() == DialogResult.OK)  //加上这句
            {
                //需要处理的程序代码
              }      
  } 

Answer 5

把你这句“textBox1.Text = openFileDialog1.FileName; ”放到上面我说的需要处理的代码处

Answer 6

正解，lz应该是没弹出对话框吧？因为没调用
if (openFileDialog1.ShowDialog() == DialogResult.OK)
加上这个就ok了

Answer 7

            openFileDialog1.ShowDialog(); 
            openFileDialog1.Title = "Open Image File"; 
            openFileDialog1.Filter = "Bitmap Files|*.bmp"; 
            openFileDialog1.FileName = ""; 
            
            textBox1.Text = openFileDialog1.FileName; 

Answer 8

if (openFileDialog1.ShowDialog() == DialogResult.OK) 
加上这个了，但还是没有出现对话框啊！怎么回事呢？

Answer 9

加断点跟踪一下，要是没出现对话框，估计程序没走进click事件里

Answer 10

if (openFileDialog1.ShowDialog() == DialogResult.OK) 
加不加这个无所谓，就这段代码不加也应该出对话框，估计楼上说的可能比较大！

Answer 11

有可能是Program.cs除了问题在
 static void Main()
        {
            
        }
之前应该有个
[STAThread]
没有的话填上