怎样写SelectNodes 可以获取到以上xml的name值

Question

<Form>
  <Name>1</Name>
</form>
<Form>
  <Name>2</Name>
</form>
<Form>
  <Name>3</Name>
</form>
<Form>
  <Name>3</Name>
</form>
<Form>
  <Name>4</Name>
</form>XmlNodeList ndList = root.SelectNodes("Form[Name=*]");怎样写SelectNodes 可以获取到以上xml的name值  我要把 1 2 3 4 放进一个list中

Answer 1

<Resource>
<Form> 
  <Name>1 </Name> 
</form> 
<Form> 
  <Name>2 </Name> 
</form> 
<Form> 
  <Name>3 </Name> 
</form> 
<Form> 
  <Name>3 </Name> 
</form> 
<Form> 
  <Name>4 </Name> 
</form> </Resource>我想获取全部name的值

Answer 2

XmlNodeList ndList = root.SelectNodes("Form/Name"); 

Answer 3

得到结果是 Name Name Name Name

Answer 4

XmlNodeList ndList = root.SelectNodes("/Form/Name");
提到所有Name的结点
foreach(XmlNode node in ndList)
{
string name = node.innerText;
}

Answer 5

XmlNodeList ndList = root.SelectNodes("Form/Name"); 
ndList[i].Text

Answer 6

XmlNodeList ndList = root.SelectNodes("Form/Name");
       
            List<string> lista = new List<string>();            foreach (XmlNode nd in ndList)
            {
               
                  
                    lista.Add(nd.InnerText);
             }输出lista结果也不对   我想得到 1 2 3 4

Answer 7

        string xml = @"<?xml version='1.0'?>    
                        <root>   
                        <Form> 
                          <Name>1 </Name> 
                        </Form> 
                        <Form> 
                          <Name>2 </Name> 
                        </Form> 
                        <Form> 
                          <Name>3 </Name> 
                        </Form> 
                        <Form> 
                          <Name>3 </Name> 
                        </Form> 
                        <Form> 
                          <Name>4 </Name> 
                        </Form> 
                        </root>";
        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xml);        XmlNodeList ndList = doc.SelectNodes("//Form[Name=*]");        string value = "";
        for (int i = 0; i < ndList.Count; i++)
        {
            value += ndList[i].InnerText;
        }